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mart [117]
3 years ago
15

Create a factorable polynomial with a GCF of 6. Rewrite that polynomial in two other equivalent forms. Explain how each form was

created.
Mathematics
2 answers:
mel-nik [20]3 years ago
8 0
We are asked in the problem to devise a polynomial equation that has a GCF of 6 which means each of the terms can be divided to 6. For example: 6*(x^2 + x+1) = 6x^2 + 6x +6. This polynomial is created by multiplying each terms by the number 6 which is distinguished by factoring. 
madam [21]3 years ago
7 0

Answer:

the equivalent form of 6(2x+3x+10) are 12x+18x + 60 and 30x+60

Step-by-step explanation:

Create a factorable polynomial with a GCF of 6

GCF is 6

Lets create a polynomial with 6 outside

6(2x+3x+10)

To get equivalent form we distribute 6 inside the parenthesis

12x+18x +60

12x+18x + 60 is one of the equivalent form of 6(2x+3x+10)

To get another equivalent form we combine like terms

12x+18x + 60 = 30x+60

30x + 60 is  the equivalent form of 6(2x+3x+10)

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