Answer:
Thomas can mow 75% of lawns in 1 hour
Step-by-step explanation:
Divide 3/4 to get 0.75.
The unit rate is 0.75 to 1
Hope this helps! Pls mark brainliest
Answer:
34º
Step-by-step explanation: so basically you know a complementary angle is 2 angles that make a straight line and a vertical angle crosses which means 2 angles are congruent to each other so I drew a line that bisected the angle by drawing a line that cut through the right angle and i extended a line down from the right angle so now I have a vertical angle and a complementary so from here I labeled each angle <1 <2 <3 If I know angle 3 is 56º then I know 56 plus __ equals 90º I then subtracted 56 from 90 and I got 34 and since I am trying to figure out what angle 1 is I know that angle 1 and 2 are vertical angles therefore I know they are congruent to each other so <1 = 34º
Using it's concept, it is found that the relative frequency of 6th graders who rode a car is given by:
D. 55%.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
The number of 6th graders is given by:
N6 = 576 - (219 + 189) = 168.
The number of 6th graders who rode a car is:
N6C = 168 - 75 = 93
Hence the relative frequency is given by:
r = 93/168 = 55%.
Hence option D is correct.
More can be learned about relative frequencies at brainly.com/question/14398287
#SPJ1
Exact Form:
−1/2, b = 1
-12,b=1
Decimal Form:
−0.5,b=1
IF YOU LIKE MY ANSWER PLS GIVE ME BRAINLIEST!!
The information's given in the question are of vital importance. These information's should be very useful while getting to the desired answer of the given question.Let us now concentrate on the problem that needs to be solved.
The height of the sign that casts a shadow of 4 meters is = 5 meters
Then
The height of the tree that casts a shadow of 30 meters = (5/4) * 30 meters
= 150/4 meters
= 37.5 meters
So the tree casting a shadow of 30 meters is actually 37.5 meters in height. I hope the procedure is simple enough for you to understand.
