<span><span><span>2x</span>+3</span>=<span><span>
[email protected]</span><span>x=6</span></span></span><span><span><span><span>(2)</span><span>(6)</span></span>+3</span>=15</span><span><span>15=</span><span>15</span></span>
This is your answer:
<span>Trapezoid
JKLM is congruent to trapezoid J′K′L′M′ because you can map trapezoid
JKLM to trapezoid J′K′L′M′ by reflecting it across the line y = x and
then translating it 1 unit up, which is a sequence of rigid motions.</span>
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j. Hence, The vector AB is 16i + 12j.
<h3>How to find the vector?</h3>
If we have given a vector v of initial point A and terminal point B
v = ai + bj
then the components form as;
AB = xi + yj
Here, xi and yj are the components of the vector.
Given;
The vector ab has a magnitude of 20 units and is parallel to the
vector 4i + 3j.
magnitude

Unit vector in direction of resultant = (4i + 3j) / 5
Vector of magnitude 20 unit in direction of the resultant
= 20 x (4i + 3j) / 5
= 4 x (4i + 3j)
= 16i + 12j
Hence, The vector AB is 16i + 12j.
Learn more about vectors;
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#just keep swimming I don’t know what you mean
Answer:
Missing length = 20
Step-by-step explanation:
Ratio is 16/20=4/5
25×4/5=20