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2 years ago

Consider the given function of an arithmetic sequence. f(n) = -5n + 8

Mathematics

1 answer:

Goshia [24]2 years ago

8 0

Answer:

f(9) = -37

Step-by-step explanation:

f(n) = -5n + 8

f(9) = -5(9) + 8

f(9) = -45 + 8

f(9) = -37

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The organic garden at a restaurant is rectangular in shape and has a perimeter of 84 feet. If the length lof the garden is 24 fe

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Answer: The width of the garden is 18 feet. The area of the garden is 432ft^2.

Step-by-step explanation:

84-24*2=36

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3 years ago

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2 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

$s(5) = 4*5^{3} + 5^{2} + 13*5 + 3$

$s(5) = 593$

It's position at time t = 5 is 593.

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