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dybincka [34]
3 years ago
9

What is the orbital notation for iron

Biology
1 answer:
irga5000 [103]3 years ago
8 0
I believe the answer is 3d^6 4s^2
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In a hardy-weinberg population with two alleles, a and a, that are in equilibrium, the frequency of allele a is 0.2. what is the
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The Hardy-Weinberg equation is as follows:
( {p + q})^{2}  = 1
{p}^{2}  +2pq +   {q}^{2}  = 1
Where:
(convert all % to decimals)

p= homozygous dominant
q= homozygous recessive
pq= heterozygous

While you did not specify whether the 0.2 frequency was for dominant or recessive, we can still figure out the answer.

Using the 1st equation, we can solve for the other dominant/recessive frequency:

1-0.2=0.8

Meaning that:

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So, the heterozygous frequency would be:
0.32

Hope this helps!
8 0
2 years ago
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