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2 years ago

Question 8 heeellppp plzzzzzz

Mathematics

1 answer:

Ratling [72]2 years ago

8 0

Answer:

1/4

Step-by-step explanation:

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Express in form of (2x)^4 continued product

Svetradugi [14.3K]

(2x)^4 = 16x^4 is the continued product

3 0

2 years ago

Rogers’s car loan is automatically deducting $35 from his bank account every month. How much will the deductions total for the y

MrRa [10]

Well since there is 12 months in a year you would multiply 35 by 12, so the answer is 420

4 0

3 years ago

Determine any data values that are missing from the table, assuming that the data represent a linear function.

Varvara68 [4.7K]

Answer:

c. 14

Step-by-step explanation:

Let the missing y value be y2.

If the data represent a linear function, then:

$\frac{6 - 2}{2 - 1} = \frac{y_2 - 6}{4 - 2}$

$\frac{4}{1} = \frac{y_2 - 6}{2}$

$4 = \frac{y_2 - 6}{2}$

Multiply both sides by 2

$4 \times 2 = \frac{y_2 - 6}{2} \times 2$

$8 = y_2 - 6$

Add 6 to both sides

$8 + 6 = y_2 - 6 + 6$

$14 = y_2$

The missing value is 14

6 0

3 years ago

The ratio of the number of volleyball to the number of basketballs in the P.E room is 4:7 .there are 21 basketballs . How many v

densk [106]

Let volleyball be v and let basketball be b.

v : b = 4 : 7, b = 21

v : 21 = 4 : 7

v/21 = 4/7

7*v = 4*21

v = 4*21/7

v = 4*3

v = 12

Volleyballs are 12

Hope this helps.

8 0

3 years ago

Find the area of following rhombuses. Round your answers to the nearest tenth if<br> necessary.

polet [3.4K]

Answer:

$Area =55.4ft^2$

Step-by-step explanation:

Given

The attached rhombus

Required

The area

First, calculate the length of half the vertical diagonal (x).

Length x is represented as the adjacent to 60 degrees

So, we have:

$\tan(60) = \frac{4\sqrt 3}{x}$

Solve for x

$x = \frac{4\sqrt 3}{\tan(60)}$

$\tan(60) = \sqrt 3$

So:

$x = \frac{4\sqrt 3}{\sqrt 3}$

$x = 4$

At this point, we have established that the rhombus is made up 4 triangles of the following dimensions

$Base = 4\sqrt 3$

$Height = 4$

So, the area of the rhombus is 4 times the area of 1 triangle

$Area = 4 * \frac{1}{2} * Base * Height$

$Area = 4 * \frac{1}{2} * 4\sqrt 3 * 4$

$Area =2 * 4\sqrt 3 * 4$

$Area =55.4ft^2$

7 0

3 years ago