6. If 2P and 2Q are complementary angles, m<P = 31º. What is mzQ?

You make $10.50 an hour at your part-time job and Andy makes $9.75 an hour at his full-time job. If you work a full week of 40 h

Marianna [84]

The awnser is $420.00 (10.50 X 40 = 4200)

7 0

2 years ago

7/10 - 1/2 whats the answer

Serjik [45]

To find the answer, we can use expansion to turn the fraction’s denominator to be the same:

1/2
= 1×5 / 2×5
=5/10

We can then proceed to find the answer:

7/10 - 5/10
= 2/10
= 1/5

Therefore the answer is 1/5.

Hope it helps!

7 0

2 years ago

Read 2 more answers

Helpppp meeeee pleaseee

Sedbober [7]

18 I’m pretty sure that is the answer that
U want

4 0

3 years ago

Marlene rides her bicycle to her friend jon's house and returns home by the same route. marlene rides her bike at constant spee

riadik2000 [5.3K]

To solve the problem:

Let f = distance one way distance on level ground

Let h = distance rode on the hill

Write a time equation; where Time = distance/speed:

level time + uphill time + downhill time + level time = 1hr

f/9 + h/6 + h/18 + f/9 = 1 hr

Multiply equation by 18 to get rid of the denominators

2f + 3h + h + 2f = 18

4f + 4h = 18

Simplify by dividing this by 4

f + h = 4.5 miles is took her to get to Jon’s house.

6 0

2 years ago

A digital camcorder repair service has set a goal not to exceed an average of 5 working days from the time the unit is brought i

garri49 [273]

Answer:

The degrees of freedom first given by:

$df=n-1=12-1=11$

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

$t_{\alpha}= 1.796$

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

Step-by-step explanation:

Information given

5, 7, 4, 6, 7, 5, 5, 6, 4, 4, 7, 5.

System of hypothesis

We want to test if the true mean is higher than 5, the system of hypothesis are :

Null hypothesis: $\mu \leq 5$

Alternative hypothesis: $\mu > 5$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The degrees of freedom first given by:

$df=n-1=12-1=11$

Then we can find the critical value taking in count the degrees of freedom and the alternative hypothesis and then we need to find a critical value who accumulates 0.05 of the area in the right tail and we got:

$t_{\alpha}= 1.796$

And for this case the rejection region would be:

b) Reject H0 if tcalc >1.7960

6 0

3 years ago