Find the surface area and volume
1 answer:
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Answer:
Step-by-step explanation:
Given:
Vertices of Hyperbola : (0 ± 6) or (0,6) and (0,-6)
and asymptotes at y= (±3/5)x 0r y= 3/5 x and y=-3/5 x
The vertices are of vertical hyperbola. The equation used will be:
The Center of hyperbola (h,k) =(0,0)
The Distance from vertices to center is a and a = 6 (given)
For equation we have value of h,k and a and need to find value of b
we know,
y= k ± a/b (x-h)
Values of h and k are zero
y= 0 ± a/b (x-0)
y= (± a/b ) x
We are given asymtotes at y= (± 3/5)x which is equal to y= (± a/b ) x
as a = 6 then b= 10 i.e The simplified form of 6/10 is 3/5 so value of b=10
Putting values of a,b,h and k in equation we get,
9514 1404 393
Answer:
625 square feet
Step-by-step explanation:
The greatest area of a polygon with a given perimeter is that of a regular polygon. A regular rectangle is one that has all sides the same length -- a square. The side length of a square with 100 ft perimeter is 25 ft. The area of a square with such a side length is
A = (25 ft)² = 625 ft²
The maximum possible area is 625 ft².
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In the attached, x is the length of one side. The area versus side length is plotted. The maximum is seen to be 625 ft² for a side length of 25 ft.
