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3 years ago

6

Cassie counted a survey of the students in her classes to observe the distribution of eye color. The table shows the results of

her survey. NO LINKS!!!

1 answer:

GarryVolchara [31]3 years ago

3 0

Answer:

12+58+2+8=12

(18)-

$\frac{12}{80} + \frac{2}{80} = \frac{14}{80} = \frac{7}{40}$

(19)-

$\frac{80 - 10}{80} = \frac{70}{80} = \frac{7}{8}$

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17 points if you know. Help please

vovangra [49]

Answer:

Step-by-step explanation:

Angles 153 and QRP are straight angles, and thus Angle QRP is

180 - 153, or 27 degrees.

The interior angles of the triangle must sum up to 180 degrees:

27 + (3y + 5) + (2y - 7) = 180.

combining like terms, we get:

5y - 25 = 180, or 5y = 155, or y = 31

Then Angle Q is 3(31) + 5, or 93

Angle P is 2(31) - 7, or 55, and

Angle QRP is 27 degrees (found earlier).

6 0

3 years ago

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rodikova [14]

For question 22, divide each number by 1.41 to see which one produces a quotient larger than 0.9. d is the answer.
For #23, multiple 0.155 million by 86%, the result is 133,300
again, d is the correct answer.

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3 years ago

What is algebra? What do you do with algebra?

tigry1 [53]

Algebra is a very important branch of math.

Algebra is a lot like arithmetic which means it follows all the rules of arithmetic, and it still uses the four main operations that arithmetic is built on.

In arithmetic, the only thing that was unknown was the answer to the problem. For example, 39 + 2 = 41. In algebra, we use a variable to represent the number. A variable is a letter that represents any number. The most common variable is "x".

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4 years ago

If the point x,sqrt(3)/2 is on the unit circle. What is x?

sattari [20]

Check the picture below.

if you check your Unit Circle, it'd be there.

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3 years ago

Read 2 more answers

Find the parabola whose minimum is at (−12,−2)(−12,−2) rather than the point given in the book. the parabola's equation is y=x2+

Hoochie [10]

The vertex form of the equation of a parabola is given by

$y-k=a(x-h)^2$

where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is (-12, -2), the equation of the parabola is given by

$y-(-2)=a(x-(-12))^2 \\ \\ y+2=a(x+12)^2=a(x^2+24x+144)=ax^2+24ax+144a \\ \\ y=ax^2+24ax+114a-2 \\ \\ y=x^2+24x+ \frac{114a-2}{a}$

For a = 1,

$y=x^2+24x+112$

<span>The parabola whose minimum is at (−12,−2) is given by the equation $y=x^2+ax+b$ , where a = 24 and b = 112.</span>

8 0

4 years ago