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3 years ago

HELP PLEASE AFTER THIS ILL BE DONE AND I CAN TURN IN M WORK

Mathematics

2 answers:

arsen [322]3 years ago

5 0

Answer:

A, C, E for the first one; B, C, E for the second one; B and E for the last one

Step-by-step explanation:

Vika [28.1K]3 years ago

5 0

Hope this helps! you can see congruent angles by the lines that are shown on the sides and the right angles are the squares put in the 90 degree corners. parallel lines are lines that run in the same direction and never touch eachother.

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HELP ASAPJennifer and Chris completed some chores and split the earnings in the ratio 3:2. Jennifer earned $48.

elixir [45]

Let the total earnings be = x

Jennifer and Chris split the earnings in the ratio 3:2

Jennifer earned = $48

$\frac{3x}{5}=48$

$3x=240$

x=80

Hence total earnings are $80

(a) Chris earning is = $\frac{2x}{5}=\frac{2*80}{5}=32$

Hence, Chris earns $32

(b) Jennifer spends 30% of her earnings on a book.

So, price of the book = $\frac{30}{100}\times48$

Price of book = $14.40

(c) Jennifer also buys a magazine for = $5.40

So, total money Jennifer spent on book and magazine = 14.40+5.40=19.80

Money left with Jennifer = 48-19.80= $28.20

In fractions = $\frac{28.20}{48}$

or multiplying the numerator and denominator by 10, we get

$\frac{282}{480}$ = $\frac{47}{80}$

(d) Let the original price of the shirt = x

reduction percentage on x= 40%

Price paid after reduction = 16.80

$\frac{40x}{100}=16.80$

$40x=1680$

$x=42$

Hence, the original price of the shirt was $42.

8 0

3 years ago

What is the nth term of this sequence?

lions [1.4K]

Answer:

D, you simply just add 1.3 each time.

4 0

2 years ago

3. A local store is offering 20% off regular pr

Paladinen [302]

160$ during the sale!!

6 0

3 years ago

A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coa

g100num [7]

The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

<h3><u>Solution:</u></h3>

Let "f" be the cost of 1 fries

Let "h" be the cost of 1 hamburger

<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>

8 x cost of 1 hamburger + 5 x cost of 1 fries = 24

$8 \times h + 5 \times f = 24$

8h + 5f = 24 -------- eqn 1

<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>

6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60

$6 \times h + 2 \times f = 16.60$

6h + 2f = 16.60 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

16h + 10f = 48 ------ eqn 3

Multiply eqn 2 by 5

30h + 10f = 83 -------- eqn 4

<em><u>Subtract eqn 3 from eqn 4</u></em>

30h + 10f = 83

16h + 10f = 48

( - ) ----------------------

14h = 35

Substitute h = 2.5 in eqn 1

8(2.5) + 5f = 24

20 + 5f = 24

5f = 4

Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8

5 0

3 years ago

Marta_Voda [28]

Answer:

138 fluiere, 158 ocarine, 184 viori

Step-by-step explanation:

given:

(1) fluiere + ocarine +viori = 480

(2) fluiere + ocarine =296

(3) ocarine + viori =342

din ecuatia (3) avem: viori= 342-ocarine

din ecuatia(2) avem : fluiere= 296-ocarine

in ecuatia (1) inlocuieste ce ai gasit ca sa fie o ecuatie doar cu necunoscuta ocarine: fluiere + ocarine +viori = 480

296-ocarine +ocarine+ 342-ocarine =480

296+342-480 = ocarine =158

viori = 342-158 = 184

fluiere = 296-158 = 138

8 0

2 years ago