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Ann [662]
3 years ago
8

HELP PLEASE AFTER THIS ILL BE DONE AND I CAN TURN IN M WORK

Mathematics
2 answers:
arsen [322]3 years ago
5 0

Answer:

A, C, E for the first one; B, C, E for the second one; B and E for the last one

Step-by-step explanation:

Vika [28.1K]3 years ago
5 0
Hope this helps! you can see congruent angles by the lines that are shown on the sides and the right angles are the squares put in the 90 degree corners. parallel lines are lines that run in the same direction and never touch eachother.

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Allen is showing his work in simplifying -8.3 + 9.2 - 4.4 + 3.7. Identify and explain any errors in his work or in his reasoning
Alexandra [31]
2 is the answer for this question
4 0
3 years ago
A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
statuscvo [17]
Let's start by visualising this concept.

Number of grains on square:
1   2   4   8   16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
T_n = ar^{n - 1}
T_{15} = 2^{14} = 16384

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
S_n = \frac{a(r^{n} - 1)}{r - 1}
S_{15} = \frac{2^{15} - 1}{2 - 1}
S_{15} = 2^{15} - 1 = 32767

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.
6 0
3 years ago
Read 2 more answers
I really need help guys can some one plz help me it's for 10 points
11111nata11111 [884]

Answer:

\sqrt{8}----- 2units,2units

\sqrt{7} ------\sqrt{5}units,\sqrt{2}units

\sqrt{5}-------1unit,2units

3------2units, \sqrt{5}units

Step-by-step explanation:

Use pythagorean's theorem to solve each pair individually.

The instructions say that you have the two sides (a and b) and you have to match it with their hypothenuse.

Formula: c^2=a^2+b^2

1. a=\sqrt{5}, b=\sqrt{2}

Plug this into the formula.

c=\sqrt{(\sqrt{5} )^2+(\sqrt{2})^2 }

The square here eliminates the roots.

c=\sqrt{5+2}\\ c=\sqrt{7}

2. a=\sqrt{3}, b=4

c=\sqrt{(\sqrt{3} )^2+(4)^2}\\ c=\sqrt{3+16}\\ c=\sqrt{19}

3. a=2, b=\sqrt{5}

c=\sqrt{(2)^2+(\sqrt{5})^2 }\\ c=\sqrt{4+5}\\ c=\sqrt{9}\\ c=3

4. a=2, b=2

c=\sqrt{(2)^2+(2)^2}\\ c=\sqrt{4+4}\\ c=\sqrt{8}

5. a=1, b=2

c=\sqrt{(1)^2+(2)^2}\\ c=\sqrt{1+4}\\ c=\sqrt{5}

7 0
3 years ago
Vvv Please help vvv<br><br> Find the value of x.
LenKa [72]
X=15. This is the Altitude theorem which is Altitude/Part = Altitude/Other part. In this question you would set up the proportion 9/X = X/25 and multiply cross products to get 225=X^2. Then you undo X^2 by doing the square route of 225 and then you get 15 as the final answer.
7 0
3 years ago
3x-(-3-x)=-1 <br> pls answer this
Gnom [1K]
3x +3 + x = -1
4x= -4
X= -1
7 0
3 years ago
Read 2 more answers
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