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san4es73 [151]
3 years ago
9

What is the volume of a hemisphere with a radius of 2.1 m, rounded to the nearest tenth of a cubic meter?

Mathematics
1 answer:
Art [367]3 years ago
3 0

Answer:

The volume of hemisphere is <u>19.4 cubic meter</u>.

Step-by-step explanation:

Given:

A hemisphere is with a radius of 2.1 m.

Now, to find the hemisphere volume with radius 2.1 m.

Radius\ (r) = 2.1 m.

So, we put formula to get the volume of hemisphere:

Volume=\frac{2}{3} \pi r^3\ \ \ \ \ (Taking\ the\ value\ of\ \pi =3.14)\\\\Volume=\frac{2}{3} \times 3.14\times 2.1^3\\\\Volume=\frac{2}{3} \times 3.14\times 9.26\\\\Volume=19.384\ cubic\ meter.

<u><em>Hence, the rounded to the nearest tenth of a cubic meter is 19.4 cubic meter.</em></u>

Therefore, the volume of hemisphere is 19.4 cubic meter.

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The right denominator is : 10

Number of times each prime factor

appears in the factorization of:

Prime

Factor Left

Denominator Right

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{Left,Right}

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Denote the Left Deniminator by L_Deno

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L.C.M 20

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L.C.M 20

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Step 7 :

When a fraction equals zero :

7.1 When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

-9•(m+20)

————————— • 20 = 0 • 20

20

Now, on the left hand side, the 20 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

-9 • (m+20) = 0

Equations which are never true :

7.2 Solve : -9 = 0

This equation has no solution.

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7.3 Solve : m+20 = 0

Subtract 20 from both sides of the equation :

m = -20

One solution was found :

m = -20

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