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poizon [28]
3 years ago
15

The two sides of a triangular park enclosing the right angle

Mathematics
2 answers:
alina1380 [7]3 years ago
7 0

Step-by-step explanation:

could you please mark me as the brainliest answer

Radda [10]3 years ago
6 0

Step-by-step explanation:

The sides enclosing the right angle are the perpendicular and the base of the right angled triangle.

Then the area of the triangle will be

2

1

×150×200=15,000 m

2

.

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ExtremeBDS [4]
Hi there! The answer is 9 square units

To find the area of a triangle we use the following formula:
Area = 0.5 * base * height.

The base of this triangle:
AC = 6 

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7 0
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Read 2 more answers
Q is a degree 5 polynomial that passes through the origin, has zeros i and 7 - i, and q(-1)= -520. find the equation for q​
Lunna [17]

Using the factor theorem, the equation for q is:

q(x) = 4(x^5 - 14x^4 + 51x^3 - 14x^2 + 50x)

The <em>Factor Theorem</em> states that a polynomial function with roots x_1, x_2, ..., x_n is given by:

f(x) = a(x - x_1)(x - x_2)...(x - x_n)

In which a is the leading coefficient.

In this problem:

  • Passes through the origin, so x = 0 is a zero, that is x_1 = 0.
  • x = i is a zero, and thus, it's conjugate also is, that is, x = -i, hence x_2 = i, x_3 = -i
  • x = 7 - i is a zero, and thus, it's conjugate also is, that is, x = 7 + i, hence x_4 = 7 - i, x_3 = 7 + i

Then, the equation is:

q(x) = a(x - 0)(x - i)(x + i)(x - 7 + i)(x - 7 - i)

q(x) = ax(x^2 - i^2)((x-7)^2 - i^2)

Considering that i^2 = -1

q(x) = ax(x^2 + 1)(x^2 - 14x + 50)

q(x) = ax(x^4 - 14x^3 + 51x^2 - 14x + 50)

q(x) = a(x^5 - 14x^4 + 51x^3 - 14x^2 + 50x)

q(-1) = -520 means that when x = -1, q = -520, and this is used to find a.

q(x) = a(x^5 - 14x^4 + 51x^3 - 14x^2 + 50x)

-520 = a(-1 - 14 - 51 - 14 - 50)

130a = 520

a = \frac{520}{130}

a = 4

Hence, the equation is:

q(x) = 4(x^5 - 14x^4 + 51x^3 - 14x^2 + 50x)

A similar problem is given at brainly.com/question/24380382

4 0
2 years ago
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