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marissa [1.9K]
3 years ago
9

Can someone plz help me with this one problem!!!

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

-94

Step-by-step explanation:

-69 + 5 = -74

-74 + 5 = -79

-79 + 5 = -84

-84 + 5 = -89

-89 + 5 = -94

hopw this helps

allsm [11]3 years ago
5 0

Answer:

-94

Step-by-step explanation:

the rule is -5

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Now, to see if (say) angle <span>AA</span> of the triangle <span><span>ABC</span><span>ABC</span></span> is acute/right/obtuse, we need to check whether <span><span>cos∠BAC</span><span>cos⁡∠BAC</span></span> is positive/zero/negative. But what is <span><span>cos∠BAC</span><span>cos⁡∠BAC</span></span>? It is the angle made by the vectors <span><span><span>AB</span><span>−→−</span></span><span><span>AB</span>→</span></span> and <span><span><span>AC</span><span>−→−</span></span><span><span>AC</span>→</span></span>. (When you are computing the angle at a particular vertex <span>vv</span>, you should make sure that both the vectors corresponding to the two adjacent sides have that vertex <span>vv</span> as the initial point.) We will first compute these two vectors:

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Now, do the same procedure for the remaining two angles <span>BB</span> and <span>CC</span> as well. That should help you solve the problem.

A shortcut. Since you are not interested in the actual values of the angles, but you need only whether they are acute, obtuse or right, it is enough to compute only the sign of the numerator (the dot product between the vectors) in formula (1). The denominator is always positive.

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