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4 years ago

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A certain city with population of 132,000 is to be divided into 11 voting districts, and no district is to have a population tha

t is more than 10 percent greater than the population of any other district. What is the minimum possible population that the least populated district could have? A. 10,700 B. 10,800 C. 10,900 D. 11,000 E. 11,100

1 answer:

galben [10]4 years ago

4 0

Answer: Therefore, Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Number of population = 132000

Number of voting districts = 11

According to question, no district is to have a population that is more than 10 percent greater than the population of any other district.

Let the number of population that the least populated district could have be 'x'.

So, it becomes,

$x+10(1.1x)=132000\\\\x+11x=13200\\\\12x=132000\\\\x=\dfrac{132000}{12}\\\\x=11000$

Hence, there are 11000 population that the least populated district could have.

Therefore, Option 'D' is correct.

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Answer:

$1440

Step-by-step explanation:

First, find the unit rate by dividing 300 by 5, which equals 60. So, Kendra earns $60 in one day. Then, multiply 60 by 24, which equals 1440. So, Kendra makes $1440 in 24 days. Hope this helped!

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3 years ago

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Determine the value of a if one solution to the quadratic equation is x equals 5 + 3/2 I

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Step-by-step explanation:

<u>1. Determine the other solution of x</u>

If one value is 5 + $\frac{3}{2}$ then the other value is 5 - $\frac{3}{2}$

<u>2. Use reverse technique to find the equation</u>

(5 + $\frac{3}{2}$ ) (5 - $\frac{3}{2}$ ) = 0

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<u>4. Find the value of a</u>

a is the number with the variable $x^{2}$ therefore it is - $\frac{9}{4}$

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Step-by-step explanation:

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Answer:

1. $x-3=-15$
2. $2x=-24$
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Step-by-step explanation:

Given the following question:

$2x+9=-15$

To find three equations that have the same solution as the given equation we have to first solve the equation.

$2x+9=-15$
$9-9=0$
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$2x=-24$
$2x\div2=x$
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<u>Equation one:</u>
$x-3=-15$
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$-15+3=-12$
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$2x\div2=x$
$-24\div2=-12$
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<u>Equation three:</u>
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Hope this helps.

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