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2 years ago

Name the fractions from least to greatest: 40/97, 1/6, 3/41

Mathematics

2 answers:

mixer [17]2 years ago

5 0

Answer:

3/41, 1/6, 40/97

Step-by-step explanation:

stich3 [128]2 years ago

3 0

Least to greatest:

1. 1/6

2. 40/97

3. 3/41

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Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

The average grain of salt is 0.0003 meters wide. Rhinovirus, which causes the common cold, is 0.00000003 meters wide. How many t

algol [13]

Answer:

$1\times 10^4\ times$

Step-by-step explanation:

Given:

Width of average grain of salt is, $w=0.0003\ m$

Width of Rhinovirus is, $W=0.00000003\ m$

Now, expressing each width in scientific notation form, we get:

$w=0.0003\ m = 3\times 10^{-4}\ m\\\\W=0.00000003\ m = 3\times 10^{-8}\ m$

Now, in order to get how many times 'W' is wider than 'w', we divide the two widths. This gives,

$\frac{W}{w}=\frac{3\times 10^{-4}\ m}{3\times 10^{-8}\ m}\\\\\frac{W}{w}=1\times 10^{-4-(-8)}=1\times 10^{-4+8}=1\times 10^4\\\\\therefore W=1\times 10^4\times w$

Therefore, the grain of salt is $1\times 10^4\ times$ wider than Rhinovirus.

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3 years ago

Can someone please help me with this math problem. It is rate of change.

Shalnov [3]

Answer:

Step-by-step explanation:

I think 2700miles /(4+2/3) equal 578,5

8 0

2 years ago

I need help for the 5th time

Leviafan [203]

Answer:

3.2t - 2.4

Step-by-step explanation:

Given

- 3.6 - 1.9t + 1.2 + 5.1t ← collect like terms

= (- 1.9t + 5.1t) + (- 3.6 + 1.2)

= 3.2t + (- 2.4)

= 3.2t - 2.4

8 0

2 years ago

HELP ASAP I WILL GIV YOU BRAINLIST! Jim ran 200 meters in 30.4 seconds. Mac ran 100 meters in 30.4 seconds. Who ran faster?

statuscvo [17]

Jim ran faster than Mac.

3 0

3 years ago