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3 years ago

A contracter charges 1,200 for 1,100 square feet installed? It costs$ to have 1,100 feet

Mathematics

1 answer:

aleksandrvk [35]3 years ago

6 0

Answer:

$1,200

Step-by-step explanation:

You might be interested in

What Is the medían number of books<br>

TiliK225 [7]

Step-by-step explanation:

You didn't provide any numbers but in order to find the median of something you order a given list of numbers from least to greatest. After you've done this you find the number located in the middle of the number set. If there are two numbers in the middle then you add them together and divide that number by two.

Hope this helps.

8 0

4 years ago

There are 5 boxes and each box weighs x pounds. Write the expression for the total weight of the

ANEK [815]

Answer:

5x pounds

Step-by-step explanation:

Here's the solution if you need, hope it's help

8 0

2 years ago

What's the answer to these simple algebra questions.

Olegator [25]

Answer:

z = $\frac{979}{5}$ or z = 195.8

y=-30

a = 5

b = -7

x = 64

Step-by-step explanation:

5 0

3 years ago

The graph of the continuous function g, the derivative of the function f, is shown above. The function g is piecewise linear for

4vir4ik [10]

A) $g=f'$ is continuous, so $f$ is also continuous. This means if we were to integrate $g$ , the same constant of integration would apply across its entire domain. Over $0$ , we have $g(x)=2x$ . This means that

$f_{0$

For $f$ to be continuous, we need the limit as $x\to1^-$ to match $f(1)=3$ . This means we must have

$\displaystyle\lim_{x\to1}x^2+C=1+C=3\implies C=2$

Now, over $x$ , we have $g(x)=-3$ , so $f_{x$ , which means $f(-5)=17$ .

b) Integrating over [1, 3] is easy; it's just the area of a 2x2 square. So,

$\displaystyle\int_1^6g(x)=4+\int_3^62(x-4)^2\,\mathrm dx=4+6=10$

c) $f$ is increasing when $f'=g>0$ , and concave upward when $f''=g'>0$ , i.e. when $g$ is also increasing.

We have $g>0$ over the intervals $0$ and $x>4$ . We can additionally see that $g'>0$ only on $0$ and $x>4$ .

d) Inflection points occur when $f''=g'=0$ , and at such a point, to either side the sign of the second derivative $f''=g'$ changes. We see this happening at $x=4$ , for which $g'=0$ , and to the left of $x=4$ we have $g$ decreasing, then increasing along the other side.

We also have $g'=0$ along the interval $-1$ , but even if we were to allow an entire interval as a "site of inflection", we can see that $g'>0$ to either side, so concavity would not change.

5 0

3 years ago

SOMEONE PLS HELP :(!!!!!!

diamong [38]

It would be C as the answers

6 0

3 years ago