Answer:
So basically, since the formula is 2(l × w), we will do:
(Length) 2/5 + 2/5 (the same thing as multiplying it by two) which equals 4/5.
Then we do the same for the width:
(Width) 1/5 + 1/5 (also the same thing as multiplying by two) to get 2/5.
Now we just add both fractions: 4/5 + 2/5 = 1 1/5
So the answer is C.
Step-by-step explanation:
43f+128. This means that 43 is the dollar amount of f which could be any amount of feet.
Answer:
![\mu_{\hat{p}}=0.50\\\\\sigma_{\hat{p}}=0.0158](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.50%5C%5C%5C%5C%5Csigma_%7B%5Chat%7Bp%7D%7D%3D0.0158)
Step-by-step explanation:
The probability distribution of sampling distribution
is known as it sampling distribution.
The mean and standard deviation of the proportion is given by :-
![\mu_{\hat{p}}=p\\\\\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3Dp%5C%5C%5C%5C%5Csigma_%7B%5Chat%7Bp%7D%7D%3D%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
, where p =population proportion and n= sample size.
Given : According to a survey, 50% of Americans were in 2005 satisfied with their job.
i.e. p = 50%=0.50
Now, for sample size n= 1000 , the mean and standard deviation of the proportion will be :-
![\mu_{\hat{p}}=0.50\\\\\sigma_{\hat{p}}=\sqrt{\dfrac{0.50(1-0.50)}{1000}}=\sqrt{0.00025}\\\\=0.0158113883008\approx0.0158](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.50%5C%5C%5C%5C%5Csigma_%7B%5Chat%7Bp%7D%7D%3D%5Csqrt%7B%5Cdfrac%7B0.50%281-0.50%29%7D%7B1000%7D%7D%3D%5Csqrt%7B0.00025%7D%5C%5C%5C%5C%3D0.0158113883008%5Capprox0.0158)
Hence, the mean and standard deviation of the proportion for a sample of 1000:
![\mu_{\hat{p}}=0.50\\\\\sigma_{\hat{p}}=0.0158](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.50%5C%5C%5C%5C%5Csigma_%7B%5Chat%7Bp%7D%7D%3D0.0158)