Question

Which is the equation of a line with a slope of -1/3 and a Y intercept at (0,1)

Answer 1

Answer:  The required equation of the line is $x+3y=3.$

Step-by-step explanation:  We are given to find the equation of a line with slope $-\dfrac{1}{3}$ and y-intercept (0, 1).

We know that

the equation of a line with slope m and y-intercept (0, c) is given by

$y=mx+c~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

From the given information, we have

$\textup{slope, }m=-\dfrac{1}{3},\\\\\textup{y-intercept, }(0,c)=(0,1)~~~\Rightarrow c=1.$

Therefore, from equation (i), we get

$y=mx+c\\\\\Rightarrow y=-\dfrac{1}{3}x+1\\\\\Rightarrow 3y=-x+3\\\\\Rightarrow x+3y=3.$

Thus, the required equation of the line is $x+3y=3.$

Answer 2

Answer:

y = -1/3x + 1

Step-by-step explanation:

substitute the given values in y = mx + b where m is the slope and b is the y-intercept

y = -1/3x + b

at point (0, 1)

1 = -1/3 × 0 + b

1 = 0 + b

b = 1

y = -1/3 + 1