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ivanzaharov [21]
3 years ago
13

Which is the constant of proportionality for the relationship shown in the table?

Mathematics
1 answer:
baherus [9]3 years ago
3 0

Answer:

3/2

Step-by-step explanation:

you notice that the x column grows by three every time you go down. And the y column grows by 2. X is over Y so 3/2

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2 years ago
Which set of values could be from a direct proportion
mr Goodwill [35]

Answer:

First table

Step-by-step explanation:

We have to find the set of value which could be from a direct proportion.

We know that

Direct proportion :

When x is directly proportional to y

x\propto y

x=ky

Where k=Proportionality constant

k=\frac{x}{y}

K remain constant when x and y are in direct proportion

From first table

k=\frac{\frac{1}{2}}{6}=\frac{1}{12}

k=\frac{1}{12}

k=\frac{2}{24}=\frac{1}{12}

K=\frac{3}{36}=\frac{1}{12}

When x and y are both varies then ratio of x and y remain constant.Hence, it is in direct proportion.

From second table

k=\frac{0}{0}= not ]define

k=\frac{1}{1}=1

It is not direct proportion because k does not remain constant.

From third table

k=\frac{0}{2}=0

k=\frac{2}{4}=\frac{1}{2}

It is not direct proportion because k does not remain constant.

3 0
3 years ago
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A surveyor is measuring the distance across a small lake. He has set up his transit on one side of the lake 130 feet from a pili
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Answer:

x = 225.16 feet

Step-by-step explanation:

Given that,

The angle between the piling and the pier is 60°.

A surveyor has set up his transit on one side of the lake 130 feet from a piling that is directly across from a pier on the other side of the lake.

We need to find the distance between the piling and the pier. Let the distance be d. Using the trigonometry to find it as follows :

\tan(60)=\dfrac{x}{130}\\\\x=\tan(60)\times 130\\\\x=225.16\ feet

So, the required distance is 225.16 feet.

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Answer:

the answer to your question is 9.73

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