All categories

3 years ago

A commercial greenhouse is constructed

Mathematics

1 answer:

Llana [10]3 years ago

4 0

9514 1404 393

Answer:

155.52 m³

Step-by-step explanation:

The volume will be the product of the end area and the length of the greenhouse.

The end area consists of 4 triangles and 6 rectangles. We can do a little manipulation of the shapes to simplify the area calculation a bit.

We can divide half of the greenhouse face along its vertical lines to make two trapezoids. Their "bases" will be the lengths of the vertical lines, and their heights will be the dimensions 1.8 m and 0.6 m. Since there are two of each, we can find the end area to be ...

A = 2(1/2)(b1 +b2)(h1) +2(1/2)(b2 +b3)(h2)

A = (3.3 +2.7)(1.8) +(2.7 +0.9)(0.6) = 10.8 +2.16 = 12.96 . . . square meters

The volume is then ...

V = Bh

V = (12.96 m²)(12 m) = 155.52 m³ . . . . greenhouse volume

You might be interested in

Jill and Ben have the same pens Jill has 3 full boxes of pen and 2 loose pens Ben has 2 full boxes of pen and 14 loose pens how

defon

Let x be the number of pens in a box.

Jill : three full boxes of pen and 2 loose pens. 3x + 2
Ben: two full boxes of pen and 14 loose pens. 2x + 14

Jill and Ben have the same pens.
Jill = Ben
3x+2 = 2x + 14
3x - 2x = 14 - 2
1x = 12
x = 12

To check:
Jill    =   Ben
3x + 2    =   2(x) + 14
3(12) + 2 =   2(12) + 14
36 + 2 =   24 + 14
38 = 38

There are 12 pens or a dozen of pens in a full box.

8 0

3 years ago

The measures, in degrees, of the three angles of a triangle are given by 2x+1, 3x - 3, and 9x. What is the

valentinak56 [21]

Answer:

Step-by-step explanation:

27 degrees

6 0

3 years ago

Identify the correct corresponding parts

andrey2020 [161]

Answer:

The correct corresponding part is;

$\overline {CB}$ ≅ $\overline {CD}$

Step-by-step explanation:

The information given symbolically in the diagram are;

ΔCAB is congruent to ΔCED (ΔCAB ≅ ΔCED)

Segment $\overline {CA}$ is congruent to $\overline {CE}$ ( $\overline {CA}$ ≅ $\overline {CE}$ )

Segment $\overline {CB}$ is congruent to $\overline {CD}$ ( $\overline {CB}$ ≅ $\overline {CD}$ )

From which, we have;

∠A ≅ ∠E by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∠B ≅ ∠D by CPCTC

Segment $\overline {AB}$ is congruent to $\overline {DE}$ ( $\overline {AB}$ ≅ $\overline {DE}$ ) by CPCTC

Segment $\overline {AE}$ bisects $\overline {BD}$

Segment $\overline {BD}$ bisects $\overline {AE}$

Therefore, the correct option is $\overline {CB}$ ≅ $\overline {CD}$

3 0

3 years ago

What is the common ratio for the sequence 28,14,7,3.5 ?

wolverine [178]

Answer:

Its 2

Step-by-step explanation:

7 0

3 years ago

An integer is chosen between 0 and 100. What is the probability that it is divisible by 7?

IgorC [24]

Assuming 0 and 100 are included in the possible choices:

There are $\left\lfloor\dfrac{101}7\right\rfloor=14$ multiples of 7 between 0 and 100, so there is a $\dfrac{14}{101}\approx0.1386$ probability of choosing a multiple of 7.

8 0

3 years ago