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Bingel [31]
3 years ago
9

For a parallel structure of identical components, the system can succeed if at least one of the components succeeds. Assume that

components fail independently of each other and that each component has a 0.11 probability of failure.
(a) Would it be unusual to observe one component fail?
(b) Would it be unusual to observe two components fail?
(c) What is the probability that a parallel structure with 2 identical components will succeed?
(d) How many components would be needed in the structure so that the probability the system will succeed is greater than 0.9999? Round to nearest whole number
Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0
So the question wants to choose among the following choices that states and support the said question and base on my understanding, I would say that the answer would be letter (d) How many components would be needed in the structure so that the probability the system will succeed is greater than 0.9999? Round to nearest whole num
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Answer:

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Step-by-step explanation:

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So First, lets solve the <u>Parenthesis</u>. -2/5=-.4

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Answer:

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Step-by-step explanation:

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kogti [31]
I and III seem to be correct, II doesn't because, for example, if x = w = z = t = 70 and y = u = 40, then all three pairs of vertical angles in the figure have equal measure and the given condition x + y = u + w stands. But it means y is not equal to w.
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