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3 years ago

Question 6 of 10

Mathematics

1 answer:

Marizza181 [45]3 years ago

5 0

B is the right answer
f(x) = x-3
y= x-3
x= y-3
x+3 =y
f^-1(x) = x+3

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PLS HELP ASAP 30 POINTS

VARVARA [1.3K]

Answer:

$\frac{23}{50}$

Step-by-step explanation:

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3 years ago

Find the inflection point of the function of f(x) = x³ -6x² +12x

Wewaii [24]

Points of inflections are zeroes of the second derivative. We have:

$f(x)=x^3-6x^2+12x\implies f'(x)=3x^2-12x\implies f''(x)=6x-12$

So, the second derivative equals zero if and only if

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3 years ago

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Bezzdna [24]

Answer:

(x, y) = (0, 3)

Step-by-step explanation:

(x, y) = (0, 3) is in both tables. Hence, that point is a solution to the system of equations.

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3 years ago

A survey was conducted that asked 1003 people how many books they had read in the past year. Results indicated that x overbar eq

Sergio [31]

Answer:

The 99% confidence interval would be given (11.448;14.152).

Step-by-step explanation:

1) Important concepts and notation

A confidence interval for a mean "gives us a range of plausible values for the population mean. If a confidence interval does not include a particular value, we can say that it is not likely that the particular value is the true population mean"

$s=16.6$ represent the sample deviation

$\bar X=12.8$ represent the sample mean

n =1003 is the sample size selected

Confidence =99% or 0.99

$\alpha=1-0.99=0.01$ represent the significance level.

2) Solution to the problem

The confidence interval for the mean would be given by this formula

$\bar X \pm z_{\alpha/2} \frac{s}{\sqrt{n}}$

We can use a z quantile instead of t since the sample size is large enough.

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.