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3 years ago

Find the value of a. 19 in a 99 in Perimeter 238 inches

Mathematics

1 answer:

Sonja [21]3 years ago

6 0

Answer:

the answer is 60 inches

Step-by-step explanation:

you have to subtract the perimeter and the numbers that are shown after you add them

238-118= 120 then you have to divide that in half wich =60.

so (A)= to 60 inches.

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Two angles that share a common endpoint and a common ray to measure of 1/4 turn

ElenaW [278]

Look at https://quizlet.com/subject/term%3Aangles%20%3D%20two%20rays%20with%20a%20common%20endpoint%20form%2... and it will help you tremendously.

6 0

2 years ago

Help me someone:((!!!!!

LiRa [457]

Answer:

Hope this helps!

Step-by-step explanation:

2L + 3S = 83

4L + 8S = 197

Multiplies the top equation by -2.

-4L + -6S = -166

4l + 8S = 197

Adding them together...

2S = 31

S = 31/2 = 15.5

Plugging into the first equation:

2L + 3S = 83

2L + 3(15.5) = 83

2L + 46.5 = 83

2L = 83 - 46.5

2L = 36.5

L = 36.5/2 = 18.25

check:

2L + 3S = 2(18.25) + 3(15.5) = 36.5 + 46.5 = 83

4L + 8S = 4(18.25) + 8(15.5) = 73 + 124 = 197

The Large box weighs 18.25

The small box weighs 15.5

6 0

2 years ago

On a piece of paper, use a protractor to construct a triangle with angle measures of 50° and 70º.

Firlakuza [10]

Hello my Kings and Queens the answer would be 60 degrees because all angles of a triangle always add up to 180 degrees

7 0

3 years ago

Read 2 more answers

Find the probability of each event. A gambler places a bet on a horse race. To win, he must pick the top three finishers in any

Lina20 [59]

Answer: $\dfrac{1}{56}$

Step-by-step explanation:

Total horses = 6

Number of ways to choose top 3 finishers in order = 3! = 6

Number ways to select 3 horses out of 8 in order = $^8P_3$ [By permutations]

$=\dfrac{8!}{(8-3)!}=\dfrac{8!}{5!}=8\times7\times6=336$

Now, the probability that the gambler will win his bet =

$\dfrac{\text{Number of ways to choose top 3 finishers }}{\text{Number ways to select 3 horses out of 8 in order}}$

$=\dfrac{6}{336}\\\\=\dfrac{1}{56}$

Hence, the required probability = $\dfrac{1}{56}$

3 0

3 years ago

The distribution of the amount of a customer’s purchase at a convenience store is approximately normal, with mean $15.50 and sta

viktelen [127]

Answer:

0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00

Step-by-step explanation:

Mean = $\mu = 15.50$

Standard deviation = $\sigma = 1.72$

We are supposed to find the proportion of customer purchase amounts between $14.00 and $16.00

P(14<x<16)

Formula : $z=\frac{x-\mu}{\sigma}$

At x = 14

$z=\frac{14-15.50}{1.72}$

$z=-0.8720$

Refer the z table for p value

P(x<14)=0.1922

At x = 16

$z=\frac{16-15.50}{1.72}$

$z=0.290$

Refer the z table for p value

P(x<16)=0.6141

P(14<x<16)=P(x<16)-P(x<14)=0.6141-0.1922=0.42

So, Option C is true

Hence 0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00

4 0

3 years ago