2 years ago

Preform the indicated operation. (w^3+64) divided (4+w)

Mathematics

1 answer:

KIM [24]2 years ago

4 0

Answer:

$\bold{w^2-4w+16}$

Step-by-step explanation:

Rewrite Equation

$\bold{\frac{w^3+64}{4+w}}$

Factor $\bold{w^3+64}$

$\bold{\left(w+4\right)\left(w^2-4w+16\right)}$

Rewrite Equation

$\bold{\frac{\left(w+4\right)\left(w^2-4w+16\right)}{4+w}}$

Cancel The Common Factor: $\bold{w+4}$

$\bold{w^2-4w+16}$

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If f(x)=-2x-3 find the value f(4y)

jasenka [17]

Answer:

f(4y) = -8y - 3

Step-by-step explanation:

Step 1: Define variables

f(x) = -2x - 3

f(4y) = x = 4y

Step 2: Plug in x = 4y

f(4y) = -2(4y) - 3

f(4y) = -8y - 3

4 0

3 years ago

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating

MakcuM [25]

Answer:

A=8.4063 $u^{2}$

Step-by-step explanation:

Be the functions:

$y=\frac{3}{x};y=\frac{3}{x^{2}}:x=7$

according the graph:

$\int\limits^1_7 {\frac{3}{x} } \, dx -\int\limits^1_7 {\frac{3}{x^{2} } } \, dx =3\int\limits^1_7 {\frac{1}{x} } \, dx -3\int\limits^1_7 {\frac{1}{x^{2} } } \, dx=3(\int\limits^1_7 {\frac{1}{x} } \, dx -\int\limits^1_7 {\frac{1}{x^{2} } } \, dx)=3[lnx-\frac{1}{x}](1-7)=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}$