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3 years ago

QUICK SOLVE 2y=x+6 show work !!!

Mathematics

2 answers:

marusya05 [52]3 years ago

8 0

Answer:

y=0.5x+3

Step-by-step explanation:

Divide both sides by 2 which will give you y=0.5x+3.

Igoryamba3 years ago

8 0

Answer:

There are many ways to solve could you specify, like what in particular do you need it solved for?

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To approximate the number of bees in a hive, multiply the number of bees that leave the hive in one minute by 3 and divide by 0.

AlekseyPX

Answer:

There are about 5,357 bees in the hive

Step-by-step explanation:

Let

x -----> the number of bees that leave the hive in one minute

y -----> the approximate number of bees in a hive

we know that

The formula to calculate the approximate number of bees in a hive is equal to

$y=\frac{3x}{0.014}$

For x=25

substitute

$y=\frac{3(25)}{0.014}$

$y=5,357\ bees$

therefore

There are about 5,357 bees in the hive

6 0

4 years ago

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The Pythagorean theorem, also known as the pythagoras’ theorem, is a fundamental relation in the geometry among the three sides

PtichkaEL [24]

Answer:

it states: a squared + b squared = c squared ( the hypotenuse)

Step-by-step explanation:

3 0

3 years ago

Solve 10% off $29 pls!!!!!!!!!!!!!!!!!!!! help 20points

kompoz [17]

Answer: the answer is 2.9 US$

4 0

3 years ago

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g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

3 years ago

PLZ HELP FASt flvyofgoyv7

Vlada [557]

Answer:

It's a function, none.

good luck, i hope this helps :)

3 0

3 years ago