7x+ 5 ! you combine the xs together as well as 7-2 which gives you 5 :)
6x^2+5x-6 would be your answer! :)
Answer:
1-c
2-d
3-a
4-b
Step-by-step explanation:
<h3>
Answer: x = -12</h3>
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Work Shown:
Let's label angle 2 as y, so y = x+132.
Also, let's add another variable z. We'll make z equal to the angle adjacent and supplementary to angle y. So y+z = 180
Solve for z to get
z = 180-y
z = 180-(x+132)
z = 180-x-132
z = 48-x
This angle z is added to the 90 degree angle to get the measure of the exterior angle 150 degrees. This is through the remote interior angle theorem.
So,
z+90 = 150
48-x+90 = 150
138-x = 150
-x = 150-138
-x = 12
x = -12
Answer:
a) 0.4121
b) $588
Step-by-step explanation:
Mean μ = $633
Standard deviation σ = $45.
Required:
a. If $646 is budgeted for next week, what is the probability that the actual costs will exceed the budgeted amount?
We solve using z score formula
= z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = $646
z = 646 - 633/45
z = 0.22222
Probability value from Z-Table:
P(x<646) = 0.58793
P(x>646) = 1 - P(x<646) = 0.41207
≈ 0.4121
b. How much should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16? (Round your answer to the nearest dollar.)
Converting 0.16 to percentage = 0.16 × 100% = 16%
The z score of 16%
= -0.994
We are to find x
Using z score formula
z = (x-μ)/σ
-0.994 = x - 633/45
Cross Multiply
-0.994 × 45 = x - 633
-44.73 = x - 633
x = -44.73 + 633
x = $588.27
Approximately to the nearest dollar, the amount should be budgeted for weekly repairs, cleaning, and maintenance so that the probability that the budgeted amount will be exceeded in a given week is only 0.16
is $588