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melomori [17]
3 years ago
12

Solve: -4 <-2x + 2 < 10

Mathematics
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

3 > x > − 4 and your welcome bud

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If a+b+c =0 show that a³+b³+c³= 3abc
slega [8]

Answer:

Step-by-step explanation:

a+b+c=0, a+b=-c,a+c=-b, b+c=-a

(a+b+c)^3=(a+b+c)^2*(a+b+c)=(a^2+b^2+c^2+2ab+2ac+2bc)*(a+b+c)=

a^3+ab^2+ac^2+2a^2b+2a^2c+2abc+a^2b+b^3+bc^2+2ab^2+2abc+2b^2c+a^2c+b^2c+c^3+2abc+2ac^2+2bc^2=a^3+b^3+c^3+3a^2b+3a^2c+3ac^2+3ab^2+3bc^2+3b^2c+6abc=

a^3+b^3+c^3+3a^2*(b+c)+3c^2(a+b)+3b^2(a+c)+6abc=

a^3+b^3+c^3+3a^2*(-a)+3c^2*(-c)+3b^2*(-b)+6abc=

a^3+b^3+c^3-3a^3-3c^3-3b^3+6abc=

6abc-2a^3-2b^3-2c^3=2(3abc-a^3-b^3-c^3)=

2*[3abc-(a^3+b^3+c^3)]=0

so 3abc-(a^3+b^3+c^3)=0

so a^3+b^3+c^3=3abc

7 0
3 years ago
Susan was given the following number to convert to scientific notation: 12,050,000 Her answer was 1.25 x 10^7 , but it was marke
KATRIN_1 [288]

Answer:

C. She left out a zero between the two and the five

Step-by-step explanation:

Given that Susan is expected to convert 12,050,000 to scientific notation, what Susan should have done is shown below:

Count the number of decimal places from your right up to before the first digit, and place the decimal point after the first digit. The number of decimal places counted would determine the exponent we are to use.

Here, we have 7 decimal places, counting from the right to the left, therefore, the exponent would be a positive 7.

What Susan should have is:

1.205 × 10⁷ NOT 1.25 × 10⁷.

1.25 × 10⁷ = 12,500,000, which is different from 12,050,000.

Her paper was marked wrong because: "she left out a zero between the two and the five"

7 0
3 years ago
Rewrite the expression using the distributive property and the gcf 35+42
forsale [732]

Answer: 7(5+6)

Step-by-step explanation:

The greatest common factor is the largest number that can both be divisible by 35 and 42

The distributive property is where a number is distributed to both numerals in the equation

8 0
3 years ago
Read 2 more answers
How do I do this? Please explain in detail.
umka2103 [35]
22.5/(x-6) + 22.5/(x+6) = 9
multiply by x-6
=> (x-6)22.5/(x-6) + (x-6)22.5/(x+6) = 9(x-6)
=> 22.5 + (x-6)22.5/(x+6) = 9(x-6)
multiply by x+6
=> (x+6)22.5 + (x+6)(x-6)22.5/(x+6) = 9(x-6)(x+6)
=> (x+6)22.5 + (x-6)22.5 = 9(x-6)(x+6)
distribute
=> 22.5x+6(22.5) + 22.5x - 6(22.5) = 9(x^2 - 36)
=> 45x = 9x^2 - 9(36)
=> 0 = 9x^2 - 45x - 9(36)
divide by 9
=> 0 = x^2 - 5x - 36
=> 0 = x^2 - 5x - 36
=> 0 = (x - 9)(x + 4)
x=9 and -4
8 0
3 years ago
Read 2 more answers
Which of the following is not a way to represent the solution of the inequality 2(x − 1) greater than or equal to −12?
grandymaker [24]
2(x - 1) > = -12
2x - 2 > = -12
2x > = -12 + 2
2x > = -10
x > = -10/2
x > = -5 or -5 < = x

wrong solution would be B. x less then or equal to -5....because x is greater then or equal to -5


5 0
3 years ago
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