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3 years ago

At the beginning of spring, Gabriella planted a small sunflower in her backyard.

Mathematics

1 answer:

Agata [3.3K]3 years ago

4 0

Answer:

The sunflower be 40 inches tall after 4 weeks.

Total height of sunflower in w weeks = 20+1.5 w,

Step-by-step explanation:

Given: In the beginning, the sunflower was 20 inches tall.

The sunflower then began to grow at a rate of 1.5 inches per week.

Then, total height of sunflower in 4 weeks = 10+1.5 ×10, where 1.5 ×10= growth in 4 weeks

= 20+20 = 40 inches

So, the sunflower be 40 inches tall after 4 weeks.

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Question 4) Identify the surface area of the composite figure.

nignag [31]

The surface area of the composite figure is 714 sq. in.

<h3>What is formula of surface area of cube ?</h3>

Let, a be the edge of the cube.

Then, surface area of the cube = 6a² square unit

<h3>What is formula of surface area of cuboid ?</h3>

Let, length of the cuboid = l unit

Width of the cuboid = w unit

Height of the cuboid = h unit

Then, surface area of the cuboid = 2(lw+lh+hw) square unit

<h3>What is the required surface area ?</h3>

Given, edge of cube = 4 in.

∴ Surface area of cube = (6×4²) sq. in. = 96 sq. in.

Now, given, length of cuboid = 15 in.

Width of the cuboid = 10 in. & height of the cuboid = 7 in.

∴ Surface area of the cuboid = 2{(15×10)+(15×7)+(10×7)} sq. in.

= 2{150+105+70} sq. in.

= 2{325} sq. in. = 650 sq. in.

Here, we have to find the surface area of the composite figure.

We have to subtract the surface area from both of cube & cuboid, where they are attached.In that case, we have to subtract (4×4) from both.

So, we have to subtract 2(4×4) sq. in. = 32 sq. in.

∴ The surface area of the composite figure = (650+96-32) sq. in.

= 714 sq. in.

Learn more about composite figure here :

brainly.com/question/27915109

#SPJ10

5 0

2 years ago

Take your time! :) Not important, but I would like to know, I'm writing flashcards so I can remember when I start back in school

Sav [38]

Answer:

The LCM of two numbers is the least common multiple. You want to find the least possible number that is divisible by the two numbers. So, you can list the factors of the two numbers. If there are factors that are repeated, put the repeated factors to the side. With the remaining factors, multiply the factors by each other and the repeated factors.

For example, let's try to find the least common multiple between 10 and 15.

Factors of 10: 2 * 5

Factors of 15: 3 * 5

The repeated factor is 5.

2 and 3 are left over. 2 * 3 = 6. 6 * 5 = 30. So, that is the least common multiple.

The GCF of two numbers is the greatest common factor. You want to find the greatest factor that is included in both numbers. So, again, you can list the factors of the two numbers and find the greatest factor that is repeated between the two numbers.

For example, let's try to find the greatest common factor between 30 and 45.

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

Factors of 45: 1, 3, 5, 9, 15, 45

Between the two numbers, shared factors are 1, 3, 5, and 15. So, the greatest common factor is 15.

Hope this helps!

5 0

4 years ago

Y=3(x-5)^2+4 in standard form

Tcecarenko [31]

I hope this helps you

4 0

4 years ago

What is the area of The shaded sector of the circle

Basile [38]

Area of circle = pi r^2 = 81pi

1/3 of circle = 81pi / 3 = 27 pi units^2

answer
B. 27 pi units^2

8 0

3 years ago

Read 2 more answers

In a journey of 15 miles, two third distance was travelled with 40 mph and remaining with 60 mph. How much time does the journey

Ad libitum [116K]

The first step in solving this question is to split the journey into 2 parts. In the first part of the journey, $\frac{2}{3} \times 15 = 10$ miles are covered at a speed of 40 mph. In the second part the journey 5 miles are covered at a speed of 60 mph.

The equation to compute the time of a journey given the speed and distance is $t=\frac{d}{s}$ where $t$ is the time, $s$ is the speed and $d$ is the distance.