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weqwewe [10]
3 years ago
13

What is your opinion that we should raise the drinking/smoking ages to 21?

Mathematics
2 answers:
timofeeve [1]3 years ago
8 0
In my opinion the ages for drinking/smoking should not be raised to 21. While I am not a fan of either and they almost never lead to good things, it just seems odd to me that a person can fight for his country at 18, but can't smoke or drink.
Julli [10]3 years ago
4 0
Yes, because most teenagers or early adults make bad choices. They should raise the age so when they are actual adults they can hopefully make the right decision. 

Try looking on this website is you don't believe in my opinion. http://www.debate.org/opinions/should-the-smoking-age-be-raised-to-21
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Answer:

9 correct

Step-by-step explanation: 60% of 15 = 9

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Find the X and the Y intercept of <br> 4x-y=12
Mashcka [7]

Answer:

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y-intercept: (0, -12)

I hope this helps!

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Select each equation which is equivalent to 60% of 25.
krek1111 [17]

The equation which is equivalent to 60% of 25 are x • 1.6 = 25, 0.6 • 25 = x and x/25=60//100

Percentages can be expressed as decimals or fractions.

Given the expression 60% of 25, this can b expressed as:

  • 60% of 25 = x

where x is the result of the expression.

  • 60/100 * 25 = x

Expressing 60% as a decimal will give;

0.6 of 25  = x

0.6 * 25 = x

From the expression 60/100 * 25 = x, this can also be written as:

25 = 100/60 x

25 = 10/6 x

25 = 1.6x

Hence the equation which is equivalent to 60% of 25 are x • 1.6 = 25, 0.6 • 25 = x and x/25=60//100

Learn more on equation here: brainly.com/question/2972832

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X completes one round of a running track in 8 minutes and Y completes it in 6
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Step-by-step explanation:

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Read 2 more answers
Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first
BaLLatris [955]

Answer:

\cos(x+y) goes with -\frac{\sqrt{6}+\sqrt{2}}{4}

\sin(x+y) goes with \frac{\sqrt{6}-\sqrt{2}}{4}

\tan(x+y) goes with \sqrt{3}-2

Step-by-step explanation:

\cos(x+y)

\cos(x)\cos(y)-\sin(x)\sin(y) by the addition identity for cosine.

We are given:

\sin(x)=\frac{\sqrt{2}}{2} which if we look at the unit circle we should see

\cos(x)=\frac{\sqrt{2}}{2}.

We are also given:

\cos(y)=\frac{-1}{2} which if we look the unit circle we should see

\sin(y)=\frac{\sqrt{3}}{2}.

Apply both of these given to:

\cos(x+y)

\cos(x)\cos(y)-\sin(x)\sin(y) by the addition identity for cosine.

\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}

\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}

\frac{-\sqrt{2}-\sqrt{6}}{4}

-\frac{\sqrt{6}+\sqrt{2}}{4}

Apply both of the givens to:

\sin(x+y)

\sin(x)\cos(y)+\sin(y)\cos(x) by addition identity for sine.

\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}

\frac{-\sqrt{2}+\sqrt{6}}{4}

\frac{\sqrt{6}-\sqrt{2}}{4}

Now I'm going to apply what 2 things we got previously to:

\tan(x+y)

\frac{\sin(x+y)}{\cos(x+y)} by quotient identity for tangent

\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}

-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}

-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}

-\frac{8-2\sqrt{12}}{4}

There is a perfect square in 12, 4.

-\frac{8-2\sqrt{4}\sqrt{3}}{4}

-\frac{8-2(2)\sqrt{3}}{4}

-\frac{8-4\sqrt{3}}{4}

Divide top and bottom by 4 to reduce fraction:

-\frac{2-\sqrt{3}}{1}

-(2-\sqrt{3})

Distribute:

\sqrt{3}-2

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