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fredd [130]
3 years ago
13

Which of the following parametric equations are equivalent to the polar equation r=3 cos theta

Mathematics
2 answers:
Allushta [10]3 years ago
5 0
To solve the problem you must know that to change from Cartesian to polar coordinates you must write:
 x = rcos (θ)
 Where "r" is the radius
 Likewise y = rsin (θ)
 Therefore, in the expression r = 3cos (θ) one can write r as:
 r = x / cos (θ)
 So:
 x / cos (θ) = 3cos (θ)
 x = 3cos ^ 2 (θ)
 The same for y ...
 y = rsin (θ)
 y = 3cos (θ) sin (θ).

  Finally the correct answer is option 2.
 x = 3cos ^ 2 (θ) y = 3cos (θ) sin (θ).
cupoosta [38]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Step-by-step explanation:

isosceles trapezoid = congruent sides in pairs and the same for the angles

<h2><u><em>angle 1 = 32°</em></u></h2><h2><u><em>angles 2 & 3 = 148°</em></u></h2>

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check

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