Write ACUTE, RIGHT, OBTUSE, STRAIGHT or REFLEX for each of the following: ( 5 marks)

In the graph, what is f(O)? *

Aleonysh [2.5K]

C - 0

If you put 0 into the graph (as an x value), your output would be 0.

8 0

3 years ago

1.) What is the height of the given figure?

mart [117]

Answer:

1,846.30

Step-by-step explanation:

6 0

3 years ago

Solve<br><br> 3n - 5p + 2n = 10p for n

Tomtit [17]

3n - 5p + 2n = 10p

Since we are solving for n, you want to have all the terms containing the variable n on the left side of the equation and everything else on the right side.

Let's do this by adding 5p to both sides.

3n + 2n = 10p + 5p

Now combine like terms.

5n = 15p

Divide both sides by 5 since we are solving for the variable n.

n = 3p

7 0

4 years ago

Integrated circuits consist of electric channels that are etched onto silicon wafers. A certain proportion of circuits are defec

boyakko [2]

Answer:

$z=\frac{0.033 -0.05}{\sqrt{\frac{0.05(1-0.05)}{1000}}}=-2.467$

$p_v =P(Z>-2.467)=0.0068$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of circuits that show evidence of undercutting is significantly less than 0.05.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=33 represent the number of circuits that show evidence of undercutting

$\hat p=\frac{33}{1000}=0.033$ estimated proportion of circuits that show evidence of undercutting

$p_o=0.05$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that they reduce the rate of undercutting to less than 5%.:

Null hypothesis: $p\geq 0.05$

Alternative hypothesis: $p < 0.05$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.033 -0.05}{\sqrt{\frac{0.05(1-0.05)}{1000}}}=-2.467$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z>-2.467)=0.0068$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of circuits that show evidence of undercutting is significantly less than 0.05.

4 0

3 years ago

Yssa bought four jumbo babes of Skittles, five jumbo bags of m&ms, and seven jumbo bags of Mike’n’Ikes for $121.50. Each jum

Oduvanchick [21]

121.50 divided by 16= 7.59

3 0

3 years ago

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