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VashaNatasha [74]
3 years ago
9

What is the range of the function f(x)=12-3x for the domain (-4,-2,0,2,4)

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0
Domain is all the x values...range is the y values

f(x) = 12 - 3x...f(x) is the same as y....when x = -4
y = 12 - 3(-4)
y = 12 + 12
y = 24...so when the domain (x) is -4, the range (y) = 24

f(x) = 12 - 3x....when x = -2
y = 12 - 3(-2)
y = 12 + 6
y = 18....when domain is -2, range is 18

f(x) = 12 - 3x....when x = 0
y = 12 - 3(0)
y = 12....when domain is 0, range is 12

f(x) = 12 - 3x...when x = 2
y = 12 - 3(2)
y = 12 - 6
y = 6....when domain is 2, range is 6

f(x) = 12- 3x...when x = 4
y = 12 - 3(4)
y = 12 - 12
y = 0...so when domain is 4, range is 0

so the range is (24,18,12,6,0)

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Their LCM is 42. Now, we multiply the fractions so the denominators are both 42. !You have to multiply <u>both</u> the numerator and denominator by the same number! For 6, 6*7 is 42, so you multiply both 6 and 5 by 7. When you do this, you get 35/42. For 7, 7*6 is 42, so you have to multiply both 7 and 2 by 6. When you do this, you get 12/42. The new problem is 35/42-12/42.

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