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VashaNatasha [74]
3 years ago
9

What is the range of the function f(x)=12-3x for the domain (-4,-2,0,2,4)

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0
Domain is all the x values...range is the y values

f(x) = 12 - 3x...f(x) is the same as y....when x = -4
y = 12 - 3(-4)
y = 12 + 12
y = 24...so when the domain (x) is -4, the range (y) = 24

f(x) = 12 - 3x....when x = -2
y = 12 - 3(-2)
y = 12 + 6
y = 18....when domain is -2, range is 18

f(x) = 12 - 3x....when x = 0
y = 12 - 3(0)
y = 12....when domain is 0, range is 12

f(x) = 12 - 3x...when x = 2
y = 12 - 3(2)
y = 12 - 6
y = 6....when domain is 2, range is 6

f(x) = 12- 3x...when x = 4
y = 12 - 3(4)
y = 12 - 12
y = 0...so when domain is 4, range is 0

so the range is (24,18,12,6,0)

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<h2>Answer:</h2>

<h2>cos theta= adjacent side/ hypotenuse</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8√5+1/4 = x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenuse </h2>

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