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VashaNatasha [74]
3 years ago
9

What is the range of the function f(x)=12-3x for the domain (-4,-2,0,2,4)

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0
Domain is all the x values...range is the y values

f(x) = 12 - 3x...f(x) is the same as y....when x = -4
y = 12 - 3(-4)
y = 12 + 12
y = 24...so when the domain (x) is -4, the range (y) = 24

f(x) = 12 - 3x....when x = -2
y = 12 - 3(-2)
y = 12 + 6
y = 18....when domain is -2, range is 18

f(x) = 12 - 3x....when x = 0
y = 12 - 3(0)
y = 12....when domain is 0, range is 12

f(x) = 12 - 3x...when x = 2
y = 12 - 3(2)
y = 12 - 6
y = 6....when domain is 2, range is 6

f(x) = 12- 3x...when x = 4
y = 12 - 3(4)
y = 12 - 12
y = 0...so when domain is 4, range is 0

so the range is (24,18,12,6,0)

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<h3>There are 2 answers: choice C, choice D</h3>

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Explanation:

32% = 32/100 = 0.32

32% of 400 = 0.32*400 = 400(0.32), which adds onto the original 400 to get 400+400(0.32). This is why choice D is one of the answers.

We can factor out the GCF 400 to go from 400+400(0.32) to 400(1+0.32) which then simplifies to 400(1.32) or just 400*1.32. This shows choice C is the other answer. Using a calculator,

400+400(0.32) = 400 + 128 = 528

400*1.32 = 528

meaning that 400+400(0.32) = 400*1.32

The other answer choices result in other values, showing that they aren't equivalent to 528.

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Answer: x=-1 and y= -3

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Solve for x, x+y=-4

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Substitute -3 in x=-y - 4

x=-(-3) - 4

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x= -1

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