Answer:
-5/2 because there is -5y/2 but we have to take coefficient only so -5/2
We have that
<span>Circle 1: center (8, 5) and radius 6
</span><span>Circle 2: center (−2, 1) and radius 2
we know that
the equation of a circle is
(x-h)</span>²+(y-k)²=r²
for the circle 1---------> (x-8)²+(y-5)²=36
for the circle 2---------> (x+2)²+(y-1)²=4
using a graph tool
see the attached figure
Part A)<span>What transformations can be applied to Circle 1 to prove that the circles are similar?
we know that
r1/r2---------> 6/2------> 3
</span><span>
to prove that the circle 1 and circle 2 are similar, the radius of circle 1 </span>must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down
<span>
the answer part A) is
</span>
the radius of circle 1 must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down
Part B) <span>What scale factor does the dilation from Circle 1 to Circle 2 have?
the answer Part B) is
the scale factor is (3/1)</span>
Answer:
37< 10x-7
Step-by-step explanation:
Answer:
1/2k-3/5
Step-by-step explanation:
Answer:
Nethan made 8 rose bouquets and 6 daffodil bouquets.
Nethan only has enough flowers to make at most 20 rose or daffodil bouquets total.
Let x represents the number of more rose bouquets.
Let y represents the number of more daffodil bouquets.
The maximum bouquets that can be made = 20
And the number of bouquets made are = 14
So, additional bouquets are = 
In equation form we can show like :

or 
or 
Putting values of x as 0,2,4 and 6 we get:
When x = 0 then y = 6
When x = 2 then y = 4
When x = 4 then y = 2
When x = 6 then y = 0
You can see the graph attached.