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S_A_V [24]
3 years ago
6

Is the sum the sum of the arithmetic 1635?​

Mathematics
2 answers:
horsena [70]3 years ago
7 0

Answer:

1199

Step-by-step explanation:

There are 22 terms in the sum:

23 + 26 + 29 + ... + 80 + 83 + 86 =

= (23 + 86) + (26 + 83) + ... + (53 + 56)

= 109 + 109 + ... + 109

= 11(109)

= 1199

Troyanec [42]3 years ago
7 0
ANSWER

1199

EXPLANATION

The given series is

\sum_{n=9}^{30}(3n-4)

To find the first term of this series, we put n=9 into the formula.

a = 3(9) - 4 = 23

To find the last term, we put n=30

l = 3(30) - 4 = 86

There are 22 terms from the 9th term to the 30th term

The sum of the consecutive n-terms of an arithmetic series is given by;

S_n= \frac{n}{2} (a + l)

We substitute n=22, a=23, and l=86 to get;

S_ {22}= \frac{22}{2} (23 + 86)

S_ {22}= 11 \times 109

S_ {22}= 1199
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Answer:

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This tells us that:

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Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

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So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

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Please help!! Thanks
Troyanec [42]
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