Answer:
2,736
Step-by-step explanation:
Answer:
4y-12
Step-by-step explanation:
To multiply a sum (or difference) by a factor, each summand (or minuend and subtrahend) is multiplied by this factor and the resulting products are added (or subtracted).
If the operation outside the parentheses (in this case, the multiplication) is commutative, then left-distributivity implies right-distributivity and vice versa, and one talks simply of distributivity.
Answer:
{x,y} = {-2,-3}
Step-by-step explanation:
System of Linear Equations entered :
[1] -9x + 4y = 6
[2] 9x + 5y = -33
Graphic Representation of the Equations :
4y - 9x = 6 5y + 9x = -33
Solve by Substitution :
// Solve equation [2] for the variable y
[2] 5y = -9x - 33
[2] y = -9x/5 - 33/5
// Plug this in for variable y in equation [1]
[1] -9x + 4•(-9x/5-33/5) = 6
[1] -81x/5 = 162/5
[1] -81x = 162
// Solve equation [1] for the variable x
[1] 81x = - 162
[1] x = - 2
// By now we know this much :
x = -2
y = -9x/5-33/5
// Use the x value to solve for y
y = -(9/5)(-2)-33/5 = -3
<h2>
Answer:</h2>
y = 2
<h2>
Step-by-step explanation:</h2>
To determine the equation of the line that passes through (10,2) and (-3,2), we need to determine the slope of the line. Then substitute the slope and any given point in point slope form to obtain the equation of the line.
<h3>Finding the Slope of the line:</h3>


<u>Substitute the coordinates of the given points:</u>

<u>Simplify the equation to determine the slope:</u>

∴ 0 divided by ANY number is ALWAYS 0.

<h3>Finding the equation of the line:</h3>
Point slope form formula: y - y₁ = m(x - x₁)
- x₁ and y₁ are the coordinates of any given point.
- m is the slope
<u>Substitute the values in the point slope form:</u>


<u>Simplify the equation to determine the equation of the line:</u>
∴ Any number multiplied by 0 is 0.



Thus, the equation of the line is y = 2.
Answer:
2
Step-by-step explanation:
You have to cancel the -7 so you would add +7 to each side.
-7+7=0, -5+7= 2
y=2
Although this isn't an answer choice. Did you mistype something?