If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Answer:
The equation should be, <em><u>65m+25=c</u></em>
Answer:
points go at -3 on the line and at 9 one above the line
Step-by-step explanation:
Answer:
-4(-41)
Step-by-step explanation:
Answer:
yes, by SAS
Step-by-step explanation:
cause the GI and JL are congruent and the same for HG and LK
