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Vesnalui [34]
3 years ago
14

Please help I’ll give 40 extra points!!!

Mathematics
2 answers:
Slav-nsk [51]3 years ago
3 0

Answer:

Its the first one

Step-by-step explanation:

losing yards means negative... and then its multiplying 3 and 5

Ira Lisetskai [31]3 years ago
3 0

Answer:

It is the first 1

Step-by-step explanation:

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kow [346]

9 \times 3 \times \frac{12}{4}  = 9 \times 3 \times 3 = 81

7 0
2 years ago
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Write 107% as a decimal. Pls with solutions
otez555 [7]

Answer:

1.07

Step-by-step explanation:

1 To convert to a decimal, divide the percent number by 100.

<h3>107÷100=1.07</h3>

2 Therefore, the decimal form is 1.07

<h3>1.07</h3>

5 0
2 years ago
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What is the simplified form of the quantity y-squared plus 7y plus 12 over the quantity y-squared plus 8y plus 15
Burka [1]
Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.

7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)

Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.

Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.

This gives us our final answer:
(y+4)/(y+5)
8 0
3 years ago
Find the GCF of numbers 132 and 242 using prime factorization.
tatyana61 [14]

Answer:

1)Find the prime factorization of 242

242 = 2 × 11 × 11Step-by-step explanation:

2)Find the prime factorization of 132

132 = 2 × 2 × 3 × 11

3)To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 11

The lost one 4) GCF = 22

6 0
2 years ago
100 POINTS AND BRAINLIEST
zysi [14]

Answer:

8 square units and \frac{40}{3} square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor \frac{1}{3}, then

\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.

2. Triangles ABC and DBE are similar with scale factor \frac{2}{3}, then

\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.

3. Thus, the area of the quadrilateral DFGE is

A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.

and the area of the quadrilateral ADEC is

A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.

4 0
3 years ago
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