All categories

3 years ago

Please help.

1 answer:

6 0

If there are 4 cups in every quart, and there are 6 quarts, that mean there are 24 cups of milk. If you take 24 and divide it by 3 cups each, you will get 8 sets with 3 cups in each set. For every set, you need to add 2 eggs, so that would be 16 eggs for the total of 6 quarts.
Answer is 16 eggs.

You might be interested in

Which inequality represents all possible solutions of -6n < -12?

Helga [31]

$-6n < -12\\\\\implies 6n > 12\\\\\implies n > \dfrac{12}6\\\\\implies n > 2$

8 0

3 years ago

A cyclist estimates that he will bike 80 miles this week. He actually bikes 75.5 miles. What is the percent error of the cyclist

vazorg [7]

Answer:

Step-by-step explanation:

Estimated distance = 80 miles

Actual distance covered = 75.5 miles

We need to find the percent error of the cyclist's estimate. Its formula is given by :

$\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100$

Put all the values,

$\%=\dfrac{80-75.5}{75.5}\times 100\\\\=5.96\%$

= 6%

So, the percentage error is 6%.

4 0

3 years ago

Read 2 more answers

The Split Ends Salon orders 10 cases of hand-made hairbrushes.

r-ruslan [8.4K]

Answer:

it would take 65 hours to produce all of the order.

Step-by-step explanation:

1. you already would figure out that 26 hours=4 cases or 6.5 hours per case of hairbrushes.

2. You would figure out that 26+26 is 52 so 52 hours for 8 cases

3. Then you remember u have 8 cases of hairbrushes now. Set up a mental equation where you can solve in your mind: if I need 10 cases, but have figured out I only calculated 8, how much more would I still need to meet the order?

4. After mentally solving the hypothetical problem, you then would conclude you needed 2 more cases from 8 to equal 10.

5. you then divide 26 hours per 4 cases and you get 13 hours for 2 cases.

6. finally you multiply 26+26+13 which you would get 65 as the answer

7 0

3 years ago

Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b

Korolek [52]

Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0

4 0

3 years ago

Is 85 a prime or compistie number?

inna [77]

The number 85 is a composite number because it has more divisors than 1 and itself.

4 0

3 years ago