Answer: A #3f107f.
Letter B would produce a lighter blue-purple color rather than a darker shade of purple. Letter C would produce a very light purple color. Letter D would produce a Black color, making it very dark and not in the range of being purple.
Letter A would produce a darker shade of purple. As explained in the way that the RGB color hexadecimal uses, the amount of each respective color is 2 digits for each color Red, Green, Blue respectively. By reducing the amount of each color in the RGB mode, the output will become a darker shade as the RGB mode is an ADDITITIVE type of color mode.
Answer:
Selective Repeat protocols
Explanation:
It is better to make use of the selective repeat protocol here. From what we have here, there is a high error rate on this channel.
If we had implemented Go back N protocol, the whole N packets would be retransmitted. Much bandwidth would be needed here.
But we are told that bandwidth is limited. So if packet get lost when we implement selective protocol, we would only need less bandwidth since we would retransmit only this packet.
Answer:
d) y=x++
Explanation:
In all 3 statements:
y= ++x;
y=x=5;
y=5;
The value of y is equal to 5.
However in the statement y=x++, the value of 5 is equal to value of x prior to the increment operation. The original value of x was 4. So the value of y will be 4. Note that after the statement execution, the value of x will be updated to 5. In effect y=x++ can be visualized as a sequence of following steps:
x=4;
y=x;
x=x+1;
