Answer:
22464
Step-by-step explanation:
there
Answer:
42
Step-by-step explanation:
<h2>Perimeter of quadrilateral with inscribed circle:</h2>
Two tangents from a point outside the circle to some point to a circle are of equal lengths.
CB = 3+ 5 = 8
CD = 3+ 4 = 7
DA = 4 + 9 = 13
AB = 9+ 5 = 14
Perimeter = 8 + 7 + 13 + 14
= 42
Answer:The equation of the function shown in the graph is: A ) f (x) = log(2) ( x + 3 ) - 5 .
Step-by-step explanation:We have to choose what is the equation of the function on the graph. We know the parent function: f(x) = log(2) x ( log base 2 ). The new function should be in the form: f(x) = log(2) ( x - a ) + b. The new vertical asymptote is : x = -3, So: a = -3. Now we have: f (x) = log(2)( x + 3 ) + b. After that we will substitute the values of coordinates of the point ( - 5 , - 2 ) which belong to this function. - 5 = log(2) ( - 2 + 3 ) + b. - 5 = log (2) 1 + b ; - 5 = 0 + b; b = - 5.