Answer:
idk im dumb just like you dude
Step-by-step explanation:
~You would set up the equation x+(3x+5)=6565
~Combine like products so 3x+x=4x.
~Now you have 4x+5=6565.
~Isolate the variable by subracting the 5 from both sides, so you have 4x=6560.
~Since you multiply x by 4, divide both sides by 4, and 6560 divided by 4 is 1,640.
*The first number is 1,640.
~Now to find the second number you simply plug in 1,640 to (3x+5), with 1,640 being x.
~That would become [3(1,640)+5].
~3 times 1, 640 is 4,920, and add the 5 so you get 4,925.
*The second and larger number is 4,925.
If you wanna check just add the two numbers, and you get 6565.
Answer:
61 , 63 , 65 , 67
Step-by-step explanation:
Let the least even number be denoted by x. The sum of the four consecutive even numbers would be:
(x) + (x + 2) + (x + 4) (x + 6) = 256
First, simplify. Combine all like terms:
x + x + x + x + 2 + 4 + 6 = 256
4x + 12 = 256
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 12 from both sides of the equation:
4x + 12 (-12) = 256 (-12)
4x = 256 - 12
4x = 144
Next, divide 4 from both sides of the equation:
(4x)/4 = (144)/4
x = 144/4
x = 61
61 is your first number. Find the next 3 consecutive numbers:
x = 61
x + 2 = 63
x + 4 = 65
x + 6 = 67
Check:
61 + 63 + 65 + 67 = 256
256 = 256
~
Answer:
like here x= 3 and y= -15
here, its 5 times goes in negative
now if y = 10 TO X IS 5 TIME POSITIVE HERE = 10×5 = 50
