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Kisachek [45]
3 years ago
11

Please help with this problem from algebra II, I will give brainliest!!!

Mathematics
1 answer:
Kaylis [27]3 years ago
6 0
The answer is b , because each equation will have the open ball going to the left and the open ball going to the right.
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The sum of three consecutive integers is 267. What is the largest integer?
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n;\ n+1;\ n+2-the\ consecutive\ integers\\\\n+(n+1)+(n+2)=267\\\\n+n+1+n+2=267\\\\3n+3=267\ \ \ \ |subtract\ 3\ from\ both\ sides\\\\3n=264\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{n=88}\\\\last\ integer:n+2=88+2=90\\\\Answer:\fbox{90}
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Marizza181 [45]

Answer:

112 cm^2

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Area of a rhombus is equal to half of the product of the diagonals, so it is 14 * 2 * 8 / 2 = 14cm * 8cm = 112 cm^2.

Other point of view: It is the sum of areas of two triangles of area 14*8/2. So the area is 14*8.

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