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Mars2501 [29]
2 years ago
9

What is the answer to this questions

Mathematics
1 answer:
nadya68 [22]2 years ago
8 0
The answer would be B
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7: hundred thousands
8: ten thousands
9: thousands
2: hundreds
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3: digits
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Find an equation for the nth term of the arithmetic sequence.<br> -20, -16, -12, -8, ...
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Common difference = -16-(-20) = 4
nth term = -20+(n-1)4
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By which rule are these triangles congruent <br><br> A. AAS<br> B. ASA<br> C. SAS<br> D. SSS
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To celebrate her birthday, Whitney wants to take her friends adventuring in a 4WD vehicle from All Terrain Tours.
IgorC [24]

Answer:

Whitney can bring <u>6 friends.</u>

Step-by-step explanation:

The reason why is this:

Whitney is bringing 400 pounds of things plus <u>her own body weight! </u>

400 + 165 = 565 pounds

Now we add on Whitneys freinds which is <u>165 (their body weight) + the 10 pounds of gear which equals 175 pounds. So each friend would be 175 pounds total weight. </u>

175 x 6 = 1,050 pounds

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565 + 1,050 = 1,615

<u>Adding on another friend would be 1,790 pounds which would be over the weight limit for the vehicle. </u>

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<em>Hope this helped! :)</em>

4 0
2 years ago
How many passwords of 4 digits are there(a)if none of the digits can be repeated?(b)start with 5 and end in an even digit?
liraira [26]

Answer:

5040,56

Step-by-step explanation:

We have to construct pass words of 4 digits

a) None of the digits can be repeated

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4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)

No of passwords = 10P4

= 10(9)(8)(7)\\=5040

b) start with 5 and end in even digit

Here we restrain the choices by putting conditions

I digit is compulsorily 5 and hence only one way

Last digit can be any one of 0,2,4,6,8 hence 5 ways

Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)

=56

3 0
3 years ago
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