Now we add on Whitneys freinds which is 165 (their body weight) + the 10 pounds of gear which equals 175 pounds. So each friend would be 175 pounds total weight.

175 x 6 = 1,050 pounds

If we add on Whitneys total weight thats:

565 + 1,050 = 1,615

Adding on another friend would be 1,790 pounds which would be over the weight limit for the vehicle.

Hence, Whitney can bring along 6 friends for her birthday.

Hope this helped! :)

4 0

2 years ago

How many passwords of 4 digits are there(a)if none of the digits can be repeated?(b)start with 5 and end in an even digit?

liraira [26]

Answer:

5040,56

Step-by-step explanation:

We have to construct pass words of 4 digits

a) None of the digits can be repeated

We have total digits as 0 to 9.

4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)

No of passwords = 10P4

= $10(9)(8)(7)\\=5040$

b) start with 5 and end in even digit

Here we restrain the choices by putting conditions

I digit is compulsorily 5 and hence only one way

Last digit can be any one of 0,2,4,6,8 hence 5 ways

Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)

=56

3 0

3 years ago