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Alexxandr [17]
3 years ago
7

What is the slope? WILL MARK BRAINLIEST!! !! (picture included ^^^^)

Mathematics
2 answers:
ryzh [129]3 years ago
8 0

Answer:

answer 3

Step-by-step explanation:

irakobra [83]3 years ago
4 0

Answer:

3/2

Step-by-step explanation:

slope is rise over run

point at (0,-4) and (2,1)

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3 years ago
Hallie can use the equation p = 4l + 4w + 4h to determine the sum of the lengths of the edges of a rectangular prism. She begins
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( l+w)

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just did the question

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3 years ago
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Here is the question !
Delvig [45]

Answer:

Step-by-step explanation:

Co-ordinates of F, G and H are:

F (-4, 5)

G (1, 10)

H (-9, 10)

You can find the lengths of sides by using the distance formula:

<em>length</em>(FG) = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}} = \sqrt{(1-(-4))^{2} + (10-5)^{2}} = 5\sqrt{2} units

Similarly,

<em>length</em>(GH) = 10 units

<em>length</em>(HF) = 5\sqrt{2} units

Hence, perimeter will be:

P = <em>length</em>(FG) + <em>length</em>(GH) + <em>length</em>(HF) = 10(\sqrt{2} + 1) units

3 0
3 years ago
A population of values has a normal distribution with μ=204.9μ=204.9 and σ=81.9σ=81.9. You intend to draw a random sample of siz
marin [14]

Answer:

7. μ=204.9 and σ=5.4968

8. μ=75.9 and σ=0.7136

9. p=0.9452

Step-by-step explanation:

7. - Given that the population mean =204.9 and the standard deviation is 81.90 and the sample size n=222.

-The sample mean,\mu_xis calculated as:

\mu_x=\mu=204.9, \mu_x=sample \ mean

-The standard deviation,\sigma_x is calculated as:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{81.9}{\sqrt{222}}\\\\=5.4968

8. For a random variable X.

-Given a X's population mean is 75.9, standard deviation is 9.6 and a sample size of 181

-#The sample mean,\mu_x is calculated as:

\mu_x=\mu\\\\=75.9

#The sample standard deviation is calculated as follows:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{9.6}{\sqrt{181}}\\\\=0.7136

9. Given the population mean, μ=135.7 and σ=88 and n=59

#We calculate the sample mean;

\mu_x=\mu=135.7

#Sample standard deviation:

\sigma_x=\frac{\sigma}{\sqrt{n}}\\\\=\frac{88}{\sqrt{59}}\\\\=11.4566

#The sample size, n=59 is at least 30, so we apply Central Limit Theorem:

P(\bar X>117.4)=P(Z>\frac{117.4-\mu_{\bar x}}{\sigma_x})\\\\=P(Z>\frac{117.4-135.7}{11.4566})\\\\=P(Z>-1.5973)\\\\=1-0.05480 \\\\=0.9452

Hence, the probability of a random sample's mean being greater than 117.4 is 0.9452

7 0
3 years ago
A gardener has 27 pansies and 36 daisies. He plants an equal number of flowers in each row. What is the greatest possible number
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There would be a a row of seven and would be 9 in each row
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4 years ago
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