Answer:
Probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
Step-by-step explanation:
We are given that 20% of the candy produced are red. A random sample of 100 bags of Skittles is taken.
The distribution we can use here is;
~ N(0,1)
where, p = 0.20 and n = 100
Let 
= proportion of red candies in our sample
So, P( < 0.20) = P( < 
) = P(Z < 0) = 0.5
Therefore, probability that the proportion in our sample of red candies will be less than 20% is 0.5 .
Answer:
tens=5
Step-by-step explanation:
Using the z-distribution, it is found that the 90% confidence interval for mean calories in a 30-gram serving of all chocolate chip cookies is (143, 149).
We are given the <em>standard deviation</em> for the population, which is why the <em>z-distribution </em>is used to solve this question.
The information given is:
- Sample mean of
.
- Population standard deviation of
.
- Sample size of
.
The confidence interval is:
The critical value, using a z-distribution calculator, for a <u>95% confidence interval</u> is z = 1.645, hence:
The 90% confidence interval for mean calories in a 30-gram serving of all chocolate chip cookies is (143, 149).
A similar problem is given at brainly.com/question/16807970
Answer:
−3b−6x+2
Step-by-step explanation:
2x+4−7−3b+5−8x
=2x+4+−7+−3b+5+−8x
Combine Like Terms:
=2x+4+−7+−3b+5+−8x
=(−3b)+(2x+−8x)+(4+−7+5)
=−3b+−6x+2
Subtract L from both sides
S - L = L - L -rL
S - L = -rL
divide both sides by L
S - L/L = -rL/L
-r = S - L/L
divide both sides by -1
r = -S + L/L
