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klasskru [66]
3 years ago
14

A 300-page book is 10 inches long, 8 inches wide, and 3 4 inches tall. What is the volume of 100 pages of the book?

Mathematics
2 answers:
jenyasd209 [6]3 years ago
6 0

Answer:

20 inches cubed

Step-by-step explanation:

The only thing that will change if we want to find the volume of 100 pages of the book will be the height. Previously for the 300 pages, the height was 3/4 inches. Now, however, it will be a third of that because 100 = 300/3. So, the new height will be: (3/4) / 3 = 1/4 inches.

The length of 10 inches and width of 8 inches will still be the same. The volume of a rectangular prism (the shape of the book) is: V=lwh , where l is the length, w is the width, and h is the height.

h = 1/4

w = 8

l = 10

V = 10 * 8 * (1/4) = 80/4 = 20 inches cubed

The volume is thus 20 inches cubed.

Hope this helps!

katen-ka-za [31]3 years ago
5 0

Answer:

20 in³

Step-by-step explanation:

Volume of 300 pages:

10 × 8 × 3/4

When the no. of pages change, only the thickness of the book changes:

Volume = 10 × 8 × ¼

= 20 in³

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The function f(x) = x2. The graph of g(x) is f(x) translated to the right 3 units and down 3 units. What is the function rule fo
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The rule for g(x) is: f(x) = (x-3)^2-3

Step-by-step explanation:

Given function is:

f(x) = x^2

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f(x) = (x-3)^2-3

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The rule for g(x) is: f(x) = (x-3)^2-3

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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
3 years ago
Read 2 more answers
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