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3 years ago

Eloise made a list of some multiples of 8/5 write 5 fractions that can be in Eloise list

1 answer:

4 0

This question is asking for a list of fractions, that when you pull out common factors, they will all simplify back to the 8/5 fraction.

So if 2 is the common factor, you multiply the numerator and denominator by 2.

2: (8*2)/(5*2)= 16/10

3: (8*3)/5*3)= 24/15

4: (8*4)/(5*4)= 32/20

5: (8*5)/(5*5)= 40/25

10: (8*10)/5*10)= 80/50

Eloise's Potential List:
16/10, 24/15, 32/20, 40/25, 80/50

If you simplify any of these fractions above, you will get 8/5 again.

To work backwards:
80/50: 10 goes into 80, 10 goes into 50= 8/5

16/10: 2 goes into 16, 2 goes into 10= 8/5

Hope this helps! :)

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Solve and show your work for each question. What is 0.(24) ̅ ̅ expressed as a fraction in simplest form? What is 0.24 ̅ expresse

Elden [556K]

The answer to this question is 24/99. 0.24 with 24 repeating in fractional form is 24/99. You put a 9 in the denominator for every repeating digit.

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3 years ago

The Miller family drove 1,240 miles on their road trip. If their trip took 4 days, how many miles did they travel per day?

nikitadnepr [17]

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3 years ago

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A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that $\pi = 0.08$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a p-value of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}$

$0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}$

$\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2$

$n = 996.3$

Rounding up:

A sample of 997 is needed.

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3 years ago

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3 years ago

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Irving can I remember the correct order of the five digits on his ID number he does remember that the ID number contains the dig

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Answer: $\frac{27}{125}$

Step-by-step explanation:

Here the total numbers are 1, 4, 3, 7, 6

Since the total number of possible arrangement = $5\times 5 \times5 \times 5 \times 5=5^5$

The total number of the odd numbers in the given numbers = 3

Thus the possible arrangement that the first three digits will be odd numbers = $3\times 3\times 3\times 5\times 5=3^3\times 5^2$

Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement = $\frac{3^3\times 5^2}{5^5} = \frac{3^2}{5^{5-2}}$

= $\frac{3^3}{5^3} = \frac{27}{125}$

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3 years ago