Question

A ball is 4 feet above the ground when Tyrese throws it into the air. Use the quadratic equation 0=−t2+3t+4 to find how much time, t, it takes for the ball to reach the ground. 1 second 3 seconds 4 seconds 5 seconds

Answer 1

Answer:

its C/ 5

Step-by-step explanation:

got it wrong thanks 2 the other one lol

Answer 2

Answer:

Step-by-step explanation:

This quadratic models the parabolic motion equation

$h=-at^2+v_{i}t+h_{i}$

where h is the height of the object after the motion occurs, a is the pull of gravity, v(i) is the initial vertical velocity of the object, and h(i) is the height from which the object was initially launched.  If we are looking for when the ball hits the ground, h = 0, because the height of an object on the ground has no height at all (or 0 height).  To find the time the object was in the air, factor the quadratic and solve for the values of t.

Two factors of 4 that add up to be 3 and multiply to be 4 are -1 and 4.  So t=-1 and t = 4.  Since we know that time can never be negative, then t = 4 seconds.