A ball is 4 feet above the ground when Tyrese throws it into the air. Use the quadratic equation 0=−t2+3t+4 to find how much tim
2 answers:
Answer:
Step-by-step explanation:
This quadratic models the parabolic motion equation
where h is the height of the object after the motion occurs, a is the pull of gravity, v(i) is the initial vertical velocity of the object, and h(i) is the height from which the object was initially launched. If we are looking for when the ball hits the ground, h = 0, because the height of an object on the ground has no height at all (or 0 height). To find the time the object was in the air, factor the quadratic and solve for the values of t.
Two factors of 4 that add up to be 3 and multiply to be 4 are -1 and 4. So t=-1 and t = 4. Since we know that time can never be negative, then t = 4 seconds.
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Answer:
D. (-2,-5), (0, -7), (1, -4)
Step-by-step explanation:
From Function Theory we must remember that range of a function is the set of images related to elements of the domain. In this case, we must find the image of each of the three elements that forms the domain of , which are:
,
and
.
Then we proceed to find all elements of range:
Which corresponds to option D.