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Rus_ich [418]
3 years ago
6

Alexa has paper rectangles of different sizes of a rectangle is 7 cm longer than it is with is there a proportional relationship

between the length and width of these rectangles
Mathematics
1 answer:
Mama L [17]3 years ago
6 0
This is east just write the answer down
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152.5 is 250% of what number
MakcuM [25]
152.5 is 250% of the number, 61
7 0
4 years ago
Read 2 more answers
The line plot shows the heights of the flowers in a neighborhood garden. Part A How many flowers are in the garden? A. 5 B. 7 C.
jok3333 [9.3K]

Answer:

it's 20

Step-by-step explanation:

I just had the same question and I got it right it's 20.

5 0
4 years ago
A concession stand at an athletic event is trying to determine how much to sell cola and iced tea for in order to maximize reven
Cerrena [4.2K]

Solution :

Demand for cola : 100 – 34x + 5y

Demand for cola : 50 + 3x – 16y

Therefore, total revenue :

x(100 – 34x + 5y) + y(50 + 3x – 16y)

R(x,y)  = $100x-34x^2+5xy+50y+3xy-16y^2$

$R(x,y) = 100x-34x^2+8xy+50y-16y^2$

In order to maximize the revenue, set

$R_x=0, \ \ \ R_y=0$

$R_x=\frac{dR }{dx} = 100-68x+8y$

$R_x=0$

$68x-8y=100$  .............(i)

$R_y=\frac{dR }{dx} = 50-32x+8y$

$R_y=0$

$8x-32y=-50$  .............(ii)

Solving (i) and (ii),

4 x (i)    ⇒       272x - 32y = 400

     (ii)   ⇒   (-<u>)     8x - 32y = -50   </u>

                        264x        = 450

∴   $x=\frac{450}{264}=\frac{75}{44}$

     $y=\frac{175}{88}$

So, x ≈  $ 1.70      and    y = $ 1.99

    R(1.70, 1.99) = $ 134.94

Thus, 1.70 dollars per cola

          1.99 dollars per iced ted to maximize the revenue.

Maximum revenue = $ 134.94

4 0
3 years ago
1. Which one shows the prime factorization of 30? *
Mademuasel [1]

Answer is (a)

As in (a) all are the prime factors which guve a product of 30

4 0
3 years ago
3x^2-3x<br> ----------- -3<br> x^2-9x<br> please give me the simplified answer + explanation
STatiana [176]
You want us to simplify \frac{3x^2-3x}{x^2-9x}-3


first, factor top and bottom
3x^2-3x=3x(x-1)
x^2-9x=x(x-9)

so we have
\frac{3x(x-1)}{x(x-9)}-3=
\frac{3(x-1)}{x-9}-3
we want to combine fractions so multiply 3 by \frac{x-9}{x-9}
\frac{3(x-1)}{x-9}-\frac{3(x-9)}{x-9}=
\frac{3(x-1)-3(x-9)}{x-9}=
\frac{3x-3-3x+27}{x-9}=
\frac{24}{x-9}


the simplified answer is \frac{24}{x-9}
8 0
4 years ago
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