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Arada [10]
3 years ago
11

9 x 7 = (? x 7) - (1 x 7) = 70- ? = ?

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

70 / 7

? = 10

Step-by-step explanation:

63 = 7 * ? - 7

70 = 7 x ?

70 / 7 = ?

? = 10

yan [13]3 years ago
4 0

Answer:

-364

Step-by-step explanation:

ok so just followed the equation and got that

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gladu [14]

Answer:

for the perimeter to be made into a equation it would take the equation

2(3x - 5) + 2(2x + 1)

And for the perimeter to equal 42 x would have to equal 5

Step-by-step explanation:

so first of all we have to find our equation to equal 42:

2(3x - 5) + 2(2x + 1) = 42

you then multiply 2 for both parentheses:

(3x * 2) + (-5 * 2) + (2x * 2) + (1 * 2) = 42

so its now:

6x -10 + 4x + 2 = 42

now your going to add variables to variables and numbers to numbers:

(6x + 4x) + ( -10 + 2) = 42

to get:

10x + (-8) = 42

Now your going to add 8 to both sides:

10x + (-8) = 42

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Giving the equation:

10x = 50

now you divide both sides by 10 to get:

10x/ 10 = 50/10

x = 5

to solve you put 5 in place of the variable x:

2(3*5 - 5) + 2(2*5 + 1)

2(15 - 5) + 2(10 + 1)

20 + 22 = 42

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4 0
3 years ago
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Step-by-step explanation:

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3 years ago
Find the equation of lines a and b.
Hatshy [7]
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3 years ago
The lower supports are and the area of the two supports is square meters. The upper arch can be decomposed as one semicircle wit
Galina-37 [17]

Answer:

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The area of the archway is <u>(13.5 π</u> + 24) square meters.

Step-by-step explanation:

See attachment for the firgure,

In order to determine the area of archway = The area of upper support + area of lower support.

As given, the lower support are two congruent rectangles consists of dimension 3 m × 4 m

Therefore, the area of lower support can be written as,

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Now, the upper support arch can be decomposed as the two concentric semi circles having radius 3 m and 6 m,

Hence, the area of the upper support = Area of semi circle having radius i.e 6 m - Area of semi circle having radius i.e 3 m

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4 0
4 years ago
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Nady [450]

Answer:

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Hope this helped!

4 0
4 years ago
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